If a, b, c, d, e are consecutive positive integers such that a<b<c<d<e, then what is the positive difference between averages of Set (b, c, d, e) and (a, b, c, d)
A) 0.25
B) 0.5
C) 0.75
D) 1
E) 1.5
Source: https://www.GMATinsight.com
If a, b, c, d, e are consecutive positive integers such that
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For any set of consecutive integers, average = median.GMATinsight wrote:If a, b, c, d, e are consecutive positive integers such that a < b < c < d < e, then what is the positive difference between averages of Set (b, c, d, e) and (a, b, c, d)
A) 0.25
B) 0.5
C) 0.75
D) 1
E) 1.5
Let the five integers = 1, 2, 3, 4, 5.
Average of 2, 3, 4 and 5 = 3.5.
Average of 1, 2, 3, and 4 = 2.5.
Difference between the averages = 3.5 - 2.5 = 1.
The correct answer is D.
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GMATinsight wrote:If a, b, c, d, e are consecutive positive integers such that a<b<c<d<e, then what is the positive difference between averages of Set (b, c, d, e) and (a, b, c, d)
A) 0.25
B) 0.5
C) 0.75
D) 1
E) 1.5
We see that b = a + 1, c = a + 2, d = a + 3 and e = a + 4. The difference between the averages of the two given sets is:
(b + c + d + e)/4 - (a+ b + c + d)/4
(e - a)/4
(a + 4 - a)/4
4/4 = 1
Answer: D
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