[Math Revolution GMAT math practice question]
The points (1,6) and (7,-2) are two vertices of one diagonal of a square in the xy-plane. What is the area of the square?
A. 16
B. 25
C. 32
D. 36
E. 50
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The points (1,6) and (7,-2) are two vertices of one diagonal
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Max@Math Revolution
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Max@Math Revolution
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The length of the diagonal of the square is √{ (7-1)^2 + (6-(-2))^2 } = √100 = 10.
The side-length of the square is 10/ √2 = 5 √2 since the side-length of a square is equal to the length of its diagonal divided by √2. Thus, the area of the square is (5 √2)^2 = 50.
Therefore, E is the answer.
Answer: E
The length of the diagonal of the square is √{ (7-1)^2 + (6-(-2))^2 } = √100 = 10.
The side-length of the square is 10/ √2 = 5 √2 since the side-length of a square is equal to the length of its diagonal divided by √2. Thus, the area of the square is (5 √2)^2 = 50.
Therefore, E is the answer.
Answer: E
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Scott@TargetTestPrep
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By the distance formula, the length of the diagonal of the square is:Max@Math Revolution wrote:[Math Revolution GMAT math practice question]
The points (1,6) and (7,-2) are two vertices of one diagonal of a square in the xy-plane. What is the area of the square?
A. 16
B. 25
C. 32
D. 36
E. 50
d = √[(7 - 1)^2 + (-2 - 6)^2] = √[36 + 64] = √100 = 10.
Recall that the area of a square, given a diagonal of length d, is A = d^2/2. Thus, the area of the square is:
A = 10^2/2 = 100/2 = 50
Answer: E
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