If non- negative integers n & p are not both odd, Which of the following must be odd?
A) np
B) np +2
C) 2n+p
D)2(n +p)
E)2( n+p) +1
If non- negative integers n & p are not both odd,
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- AbhishekRyu
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A
B
C
D
E
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- Jay@ManhattanReview
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Given that n & p are not both odd, and non-negative integers, we have one of n and p even and the other is odd. With this information in mind, let's see the options.AbhishekRyu wrote:If non- negative integers n & p are not both odd, Which of the following must be odd?
A) np
B) np +2
C) 2n+p
D)2(n +p)
E)2( n+p) +1
A) np: This is a product of an even and an odd integer; note that EVEN * ODD = EVEN
B) np + 2: EVEN + EVEN = EVEN
C) 2n + p: EVEN * ? + ? => note that product of two evens and product of even and odd is even, thus, EVEN * ? + ? = EVEN + ?.
If ? or p is EVEN, 2n + p is EVEN
D) 2(n + p): EVEN * (n + p) => Product of EVEN and EVEN or ODD is EVEN. Thus, 2(n + p) = EVEN
E) 2(n + p) + 1: EVEN + ODD = ODD. Correct answer.
The correct answer: E
Hope this helps!
-Jay
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If n=p=0, options A, B, C and D each yield a even value, indicating that these options do NOT have to be odd.AbhishekRyu wrote:If non- negative integers n & p are not both odd, Which of the following must be odd?
A) np
B) np +2
C) 2n+p
D)2(n +p)
E)2( n+p) +1
Eliminate A, B, C and D.
The correct answer is E.
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So we see that n and p could be odd/even, even/odd, or both even.AbhishekRyu wrote:If non- negative integers n & p are not both odd, Which of the following must be odd?
A) np
B) np +2
C) 2n+p
D)2(n +p)
E)2( n+p) +1
Thus, since 2 times anything is even, and even + 1 is odd, 2(n + p) + 1 is odd.
Answer: E
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