Anna wants to distribute chocolates among her four children in the ratio 1/2 : 1/5 : 1/6 : 1/12. How many minimum chocolates should she buy, so that she can distribute the chocolates in the given ratio?
A. 30
B. 45
C. 57
D. 90
E. 120
The OA is C.
Source: e-GMAT
Anna wants to distribute chocolates among her four children
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Let the total number of chocolates = the LCM of the four denominators 2, 5, 6 and 12 = 60.swerve wrote:Anna wants to distribute chocolates among her four children in the ratio 1/2 : 1/5 : 1/6 : 1/12. How many minimum chocolates should she buy, so that she can distribute the chocolates in the given ratio?
A. 30
B. 45
C. 57
D. 90
E. 120
Number of chocolates given to the four children:
(1/2)(60) = 30
(1/5)(60) = 12
(1/6)(60) = 10
(1/12)(60) = 5
Total number of chocolates = 30+12+10+5 = 57.
The correct answer is C.
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\[? = \min \left( {{\text{Total}}} \right)\]swerve wrote:Anna wants to distribute chocolates among her four children in the ratio 1/2 : 1/5 : 1/6 : 1/12. How many minimum chocolates should she buy, so that she can distribute the chocolates in the given ratio?
A. 30
B. 45
C. 57
D. 90
E. 120
Source: e-GMAT
\[\frac{1}{2}\,\,:\,\,\frac{1}{5}\,\,:\,\,\frac{1}{6}\,\,:\,\,\frac{1}{{12}}\,\,\,\,\mathop \Leftrightarrow \limits_{:\,\,60}^{ \cdot \,\,60} \,\,\,\,30:12:10:5\]
\[\left\{ \begin{gathered}
{\text{Child}}\,1 = 30k \hfill \\
{\text{Child}}\,2 = 12k \hfill \\
{\text{Child}}\,3 = 10k \hfill \\
{\text{Child}}\,4 = 5k \hfill \\
\end{gathered} \right.\,\,\,\,\,\,\,\,\left( {k > 0} \right)\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,Total = 57k\,\,\,\,\,\,\mathop \Rightarrow \limits^{k\,\,\operatorname{int} \,\,\left( * \right)} \,\,\,\,\,\,? = \min \,\,\left( {{\text{Total}}} \right)\,\,\, = \,\,57 \cdot 1 = 57\]
$$\left( * \right)\,\,\,\,\left\{ \matrix{
5k\,\, = {\mathop{\rm int}} \hfill \cr
2k = 12k - 10k\,\, = \,\,{\mathop{\rm int}} - {\mathop{\rm int}} = {\mathop{\rm int}} \hfill \cr} \right.\,\,\,\,\,\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\,\,\,\,k = 5k - 2 \cdot \left( {2k} \right) = {\mathop{\rm int}} - 2 \cdot {\mathop{\rm int}} = {\mathop{\rm int}} $$
This solution follows the notations and rationale taught in the GMATH method.
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Fabio.
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Since the LCM of 2, 5, 6, and 12 is 5 x 12 = 60; we can multiply each fraction by 60 so that each fraction becomes a whole number: 1/2 x 60 = 30, 1/5 x 60 = 12, 1/6 x 60 = 10 and 1/12 x 60 = 5. Therefore, the ratio can be written as 30 : 12 : 10 : 5 and, hence, the minimum number of chocolates she should buy is 30 + 12 + 10 + 5 = 57.swerve wrote:Anna wants to distribute chocolates among her four children in the ratio 1/2 : 1/5 : 1/6 : 1/12. How many minimum chocolates should she buy, so that she can distribute the chocolates in the given ratio?
A. 30
B. 45
C. 57
D. 90
E. 120
Answer: C
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