How many multiples of 33 lie between 101 and 1,000, inclusiv

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[Math Revolution GMAT math practice question]

How many multiples of 33 lie between 101 and 1,000, inclusive?

A. 24
B. 27
C. 33
D. 36
E. 48

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by Brent@GMATPrepNow » Thu Sep 20, 2018 5:17 am
Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

How many multiples of 33 lie between 101 and 1,000, inclusive?

A. 24
B. 27
C. 33
D. 36
E. 48
Some positive multiples of 33 are: 33, 66, 99, 132, 165, 198,. . . , 957, 990, 1023
So, we want the number of multiples of 33 from 132 to 990 inclusive

Observe:
132 = (33)(4)
165 = (33)(5)
198 = (33)(6)
.
.
.
957 = (33)(29)
990 = (33)(30)

We can see that the number of multiples of 33 from 132 to 990 inclusive is the SAME as the number of integers from 4 to 30 inclusive.

To determine the above, we can apply the following rule: the number of integers from x to y inclusive equals y - x + 1
So, the number of integers from 4 to 30 inclusive = 30 - 4 + 1 = 27

Answer: B

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Brent
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by Brent@GMATPrepNow » Thu Sep 20, 2018 5:21 am
Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

How many multiples of 33 lie between 101 and 1,000, inclusive?

A. 24
B. 27
C. 33
D. 36
E. 48
Another approach is to apply the following rule:

If x and y are multiples of k, then the number of multiples of k from x to y inclusive = [(y-x)/k] + 1
So, for example, the multiples of 3 from 6 to 21 inclusive = [(21 - 6)/3] + 1 = [15/3] + 1 = 6

So, the number of multiples of 33 from 132 to 990 inclusive = (990 - 132)/33 + 1
= 858/33 + 1
= 26 + 1
= 27

Answer: B

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by GMATGuruNY » Thu Sep 20, 2018 5:31 am
Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

How many multiples of 33 lie between 101 and 1,000, inclusive?

A. 24
B. 27
C. 33
D. 36
E. 48
Since 1000 - 101 ≈ 900 -- and the answer choices are a bit spread out -- we can count the multiples of 33 simply by dividing 33 into 900:
900/33 = 300/11 = a bit more than 27.
Thus, there are 27 multiples of 33 between 101 and 1000.

The correct answer is B.
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by fskilnik@GMATH » Thu Sep 20, 2018 7:03 am
Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

How many multiples of 33 lie between 101 and 1,000, inclusive?

A. 24
B. 27
C. 33
D. 36
E. 48
One of our students´ most-loved mottos is: let the "Queen of Sciences" (Mathematics) do the weight-lifting for you!
\[? = M\,\,\,\left( {\operatorname{int} } \right)\]
\[101 < 33M < 1000\]
\[\left( {99 + 33 = } \right)\,\,\,132 \leqslant 33M \leqslant 990\,\,\,\,\left( { = 30 \cdot 33} \right)\]
\[4 \leqslant M \leqslant 30\,\,\,\, \Rightarrow \,\,\,\,? = 30 - 4 + 1 = 27\]

This solution follows the notations and rationale taught in the GMATH method.

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by Max@Math Revolution » Mon Sep 24, 2018 4:08 am
=>
Consider the arithmetic sequence 132, 165, ..., 990 of multiples of 33.
The number of terms in this sequence is (990-132)/33 + 1 = 858 / 33 + 1 = 26 + 1 = 27.

Therefore, the answer is B.
Answer: B

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by Scott@TargetTestPrep » Thu Sep 27, 2018 4:23 pm
Max@Math Revolution wrote:[Math Revolution GMAT math practice question]

How many multiples of 33 lie between 101 and 1,000, inclusive?

A. 24
B. 27
C. 33
D. 36
E. 48

The smallest multiple of 33 above 101 is 132 and the largest multiple of 33 below 1,000 is 990.

So the number of multiples is:

(990 - 132)/33 + 1 = 27

Answer: B

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