A certain investment grows at an annual interest rate of 8%, compounded quarterly. Which of the following equations can be solved to find the number of years, x, that it would take for the investment to increase by a factor of 16?
A. 16 = 1.02^(x/4)
B. 2 = 1.02^x
C. 16 = 1.08^(4x)
D. 2 = 1.02^(x/4)
E. 1/16 = 1.02^(4x)
OA B
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A certain investment grows at an annual interest rate of 8%,
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BTGmoderatorDC
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When a value increases repeatedly by r%:BTGmoderatorDC wrote:A certain investment grows at an annual interest rate of 8%, compounded quarterly. Which of the following equations can be solved to find the number of years, x, that it would take for the investment to increase by a factor of 16?
A. 16 = 1.02^(x/4)
B. 2 = 1.02^x
C. 16 = 1.08^(4x)
D. 2 = 1.02^(x/4)
E. 1/16 = 1.02^(4x)
Final amount = Original amount * (1 + r/100)^number of changes.
Let original amount = 1.
Since the original amount increases by a factor of 16:
Final amount = 16.
Since the investment increases by 2% every quarter:
r = 2.
Since x = the number of years, and there are 4 changes every year:
Number of changes = 4x.
Plugging these values into the formula:
16 = 1*(1.02)^4x
16^(1/4) = 1.02^(4x*(1/4))
2 = 1.02^x
The correct answer is B.
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I'm confused by the wording here:
It is implied in the OA that "increase by a factor of 16" means that the amount increased to 16 times its original amount.
Don't you think that "increased by a factor of 16" means x + 16x?
Hope someone clarifies this doubt! Thanks!
It is implied in the OA that "increase by a factor of 16" means that the amount increased to 16 times its original amount.
Don't you think that "increased by a factor of 16" means x + 16x?
Hope someone clarifies this doubt! Thanks!
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Scott@TargetTestPrep
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The compound interest formula is: A = P(1 + r/n)^(nt)BTGmoderatorDC wrote:A certain investment grows at an annual interest rate of 8%, compounded quarterly. Which of the following equations can be solved to find the number of years, x, that it would take for the investment to increase by a factor of 16?
A. 16 = 1.02^(x/4)
B. 2 = 1.02^x
C. 16 = 1.08^(4x)
D. 2 = 1.02^(x/4)
E. 1/16 = 1.02^(4x)
where t = the number of years, A = the amount after t years, P = the principal or the initial amount, r = the annual interest rate, and n = the number of times compounded per year.
Here, r = 8% = 0.08, n = 4, t = x. We are not given a value of P but we are given that A = 16P. So we have:
16P = P(1 + 0.08/4)^(4x)
16 = (1 + 0.02)^(4x)
16 = 1.02^(4x)
Taking the fourth root of both sides of the equation, we have:
16^(¼) = [1.02^(4x)]^(¼)
2 = 1.02^x
Answer: B
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