Economist GMAT
In the biology lab of "Jefferson" High School, there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?
A. 10
B. 20
C. 30
D. 40
E. 50
AO E.
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In the biology lab of "Jefferson" High School ther
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Brent@GMATPrepNow
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Germs per dish = (total number of germs)/(total number of dishes)AAPL wrote:Economist GMAT
In the biology lab of "Jefferson" High School, there are 0.037 x 10^5 germs, equally divided among 74000 x 10^(-3) Petri dishes. How many germs live happily in a single dish?
A. 10
B. 20
C. 30
D. 40
E. 50
AO E.
total number of germs = 0.037 x 10^5
= 3700 [moved the decimal point 5 spaces to the LEFT to get 3700]
total number of dishes = 74000 x 10^(-3)
= 74 [moved the decimal point 3 spaces to the RIGHT to get 3700]
So, Germs per dish = (3700)/(74)
= (37)(100)/(37)(2)
= 100/2
= 50
Answer: E
Cheers,
Brent
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fskilnik@GMATH
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<p>
The solution above follows the notations and rationale taught in the <b>GMATH</b> method.
</p>
In the biology lab of "Jefferson" High School, there are 0.037 x 10^5 germs, equally divided among 74000 x 10^(-3) Petri dishes. How many germs live happily in a single dish?
A. 10
B. 20
C. 30
D. 40
E. 50
The solution above follows the notations and rationale taught in the <b>GMATH</b> method.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
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Scott@TargetTestPrep
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AAPL wrote:Economist GMAT
In the biology lab of "Jefferson" High School, there are 0.037*10^5 germs, equally divided among 74000*10^(-3) Petri dishes. How many germs live happily in a single dish?
A. 10
B. 20
C. 30
D. 40
E. 50
The number of germs that live happily in a single dish is:
0.037*10^5/74,000*10^(-3)
(0.037 x 100,000)/(74,000 x 1/1000)
3700/74 = 50
Answer: E
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