There are n students in a class. Of them, k boys and k girls

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There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.


OA A

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by Jay@ManhattanReview » Sun Aug 19, 2018 10:10 pm

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BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep
We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
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by Jay@ManhattanReview » Sun Aug 19, 2018 10:10 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep
We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
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by Jay@ManhattanReview » Sun Aug 19, 2018 10:11 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep
We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
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by Jay@ManhattanReview » Sun Aug 19, 2018 10:12 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep
We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
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by Jay@ManhattanReview » Sun Aug 19, 2018 10:13 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep
We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
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Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

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by Jay@ManhattanReview » Sun Aug 19, 2018 11:00 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep
We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
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Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

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by Jay@ManhattanReview » Sun Aug 19, 2018 11:01 pm

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep
We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
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Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.

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by Jay@ManhattanReview » Mon Aug 20, 2018 12:55 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

BTGmoderatorDC wrote:There are n students in a class. Of them, k boys and k girls (including Harvey and Jessica) are selected for a dance performance in which students will dance in pairs of one boy and one girl. What is the probability that Harvey will be paired with Jessica?

(1) Other than Harvey, 5 boys are selected for the dance.

(2) 8 of the k boys are not selected for the dance.

OA A

Source: Veritas Prep
We know that out of k boys, Harvey and out of k girls, Jessica are selected for the dance performance.

Harvey can be paired with any of the k girls; among k ways, only one way is such that Harvey and Jessica are paired. Thus, the probability that Harvey will be paired with Jessica = 1/k.

Only statement 1 gives the value of k; k = 1 + 5 = 6. Sufficient.

The correct answer: A

Hope this helps!

-Jay
_________________
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Locations: New York | Hyderabad | Mexico City | Toronto | and many more...

Schedule your free consultation with an experienced GMAT Prep Advisor! Click here.