A retailer orders u units of an item for which he pays d dollars. However, he mistakenly receives u - 3 items. How much was he overcharged, in terms of d and u?
A. 3d - u
B. 3du - 9
C. (3d)/u
D. (u−d)/3
E. (du)/3
A retailer orders u units of an item for which he pays d
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Hi All,
We're told that a retailer orders U units of an item for which he paid a total of D dollars, but he mistakenly receives (U - 3) items. We're asked for the amount he was overcharged, in terms of D and U. This question can be solved in a couple of different ways, including by TESTing VALUES.
IF... U=4 and D=8
then the original price per unit was $8/4 = $2 per unit
By receiving (4-3) = 1 item and paying $8 for it, the retailer was overcharged $8 - $2 = $6
Thus, we're looking for an answer that equals 6 when U=4 and D=8. There's only one answer that matches....
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
We're told that a retailer orders U units of an item for which he paid a total of D dollars, but he mistakenly receives (U - 3) items. We're asked for the amount he was overcharged, in terms of D and U. This question can be solved in a couple of different ways, including by TESTing VALUES.
IF... U=4 and D=8
then the original price per unit was $8/4 = $2 per unit
By receiving (4-3) = 1 item and paying $8 for it, the retailer was overcharged $8 - $2 = $6
Thus, we're looking for an answer that equals 6 when U=4 and D=8. There's only one answer that matches....
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
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Since the price per unit is d/u, the cost of u - 3 units is d/u x (u - 3) = (ud - 3d)/u, so the retailer was overcharged by:BTGmoderatorDC wrote:A retailer orders u units of an item for which he pays d dollars. However, he mistakenly receives u - 3 items. How much was he overcharged, in terms of d and u?
A. 3d - u
B. 3du - 9
C. (3d)/u
D. (u−d)/3
E. (du)/3
d - (ud - 3d)/u
ud/u - (ud - 3d)/u
(ud - (ud - 3d))/u
(ud - ud + 3d)/u
(3d)/u
Answer: C
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A retailer orders u units of an item for which he pays d dollars.BTGmoderatorDC wrote:A retailer orders u units of an item for which he pays d dollars. However, he mistakenly receives u - 3 items. How much was he overcharged, in terms of d and u?
A. 3d - u
B. 3du - 9
C. (3d)/u
D. (u−d)/3
E. (du)/3
So, EACH unit costs d/u dollars
However, he mistakenly receives u - 3 items.
In other words, he received 3 fewer units than he wanted
So, he paid for 3 units that he never received (i.e., he was overcharged for 3 units)
How much was he overcharged, in terms of d and u?
He was overcharged for 3 units, and EACH unit costs d/u dollars
TOTAL overcharge = (3)(d/u)
= 3d/u
Answer: C
Cheers,
Brent