Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jala's weight. Who among these 5 persons weighs the least?
A. Bahar
B. Dolly
C. Jalal
D. Laila
E. Meena
The OA is B.
It seems a little confused but we can try to solve as follows,
If B = x we get,
M = 0.6x
J = 1.2x
L = 0.22x
and D = 0.114x
Therefore the correct answer is B.
Has anyone another strategic approach to solve this PS question? Regards!
Jalal weighs twicw as much as Meena. Meena's weight is 60%
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An alternative approach is to assign weights that meet the given conditions.AAPL wrote:Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jala's weight. Who among these 5 persons weighs the least?
A. Bahar
B. Dolly
C. Jalal
D. Laila
E. Meena
Meena's weight is 60% of Bahar's weight
Let's let Bahar's weight = 100 kg
So, Meena's weight = 60 kg
Jalal weighs twice as much as Meena.
Since Meena weight 60 kg (see above) then Jalal's weight = 120 kg
Laila weighs 19% of Jala's weight
Jalal's weight = 120 kg
19% is very close to 20%
20% of 120 kg = 24 kg
So, 19% of 120 kg = a little less than 24 kg
So, Laila weighs a little less than 24 kg
NOTE: At this point, we can see that, Laila is the lightest (so far!)
Dolly weighs 50% of Laila's weight.
So, Dolly weighs LESS THAN Laila.
So, Dolly must weigh the least
Answer: D
Cheers,
Brent
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We can let Meena's weight be 60 lbs. So Jalal's weight is 120 lbs and Bahar's weight is 60/0.6 = 100 lbs. We can round 19% to 20%, so Laila is approximately 0.2 x 120 = 24 lbs and therefore, Dolly is approximately 0.5 x 24 = 12 lbs. Dolly weighs the least.AAPL wrote:Jalal weighs twice as much as Meena. Meena's weight is 60% of Bahar's weight. Dolly weighs 50% of Laila's weight. Laila weighs 19% of Jala's weight. Who among these 5 persons weighs the least?
A. Bahar
B. Dolly
C. Jalal
D. Laila
E. Meena
Answer: B
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