DS question?
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- Morgoth
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1st gadget = Crahi08 wrote:can anybody explain this?
2nd gadget = C/2 = C/2^1
3rd gadget = C/4 = C/2^2
4th gadget = C/8 = C/2^3
5th gadget = C/16 = C/2^4
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9th gadget = C/2^8
so on and so forth
(1) the sum of the costs of the third and forth gadget -$9
C/2^2 + C/2^3 = 9
You can easily solve for C. Sufficient.
(2) the sum of the costs of the second and ninth gadget is $24(2^7+1)/28
C/2 + C/2^8 = 24(2^7+1)/28
You can easily solve for C. Sufficient.
Thus, D is the answer.