A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created, that is made up of 3 senior officers and 1 junior officer, how many different committees are possible?
A. 8
B. 24
C. 58
D. 80
E. 210
The OA is D.
What is the formula that I should use here? Please, I need some help here. Thanks in advance.
A certain company employs 6 senior officers and 4 junior
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From 6 senior officers, the number of ways to choose 3 for the committee = 6C3 = (6*5*4)/(3*2*1) = 20.M7MBA wrote:A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created, that is made up of 3 senior officers and 1 junior officer, how many different committees are possible?
A. 8
B. 24
C. 58
D. 80
E. 210
Since there are 4 junior officers, the number of options for the junior officer on the committee = 4.
To combine the options above, we multiply:
20*4 = 80.
The correct answer is D.
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Take the task of creating the 4-person committee and break it into stages.M7MBA wrote:A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created, that is made up of 3 senior officers and 1 junior officer, how many different committees are possible?
A. 8
B. 24
C. 58
D. 80
E. 210
Stage 1: Select 3 senior officers
Since the order of the selected officers does not matter, we can use combinations.
We can select 3 officers from 6 senior officers 6C3 ways (= 20 ways)
Stage 2: Select 1 junior officer
There are 4 junior officers, so we can select 1 officer in 4 ways
By the Fundamental Counting Principle (FCP) we can complete the two stages (and thus select members for the committee) in (20)(4) ways (= 80 ways)
Answer: D
Note: the FCP can be used to solve the MAJORITY of counting questions on the GMAT. For more information about the FCP, watch our free video: https://www.gmatprepnow.com/module/gmat- ... /video/775
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EASY
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MEDIUM
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DIFFICULT
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- https://www.beatthegmat.com/combinations-t123249.html
Cheers,
Brent
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We need to determine how many different committees are possible with 3 senior officers and 1 junior officer from 6 senior officers and 4 junior officers. Let's first determine the number of ways to select 3 senior officers.M7MBA wrote:A certain company employs 6 senior officers and 4 junior officers. If a committee is to be created, that is made up of 3 senior officers and 1 junior officer, how many different committees are possible?
A. 8
B. 24
C. 58
D. 80
E. 210
Number of ways to select 3 senior officers from 6 of them = 6C3 = (6 x 5 x 4)/3! = 20
Next we can determine the number of ways to select 1 junior officer.
Number of ways to select 1 junior officer from 4 of them = 4C1 = 4
Thus, the number of ways to select 3 senior officers and 1 junior officer is 20 x 4 = 80.
Answer: D
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