50 children attended a carnival where cotton candy and ice cream were sold. If 14 children ate only cotton candy, 18 children ate only ice cream, and 8 children had neither cotton candy nor ice cream, how many children ate ice cream?
A. 18
B. 20
C. 24
D. 28
E. 32
The OA is D.
This is an approach to solving this question (Double Matrix Method),
1. 14 children only cotton candy, 18 only ice cream, and 8 children no cotton candy and ice cream.
2. Only one left category: both ate cotton candy and ice cream, which is 50 - 14 - 18 - 8 = 10.
3. Thus, children who ate ice cream = children ONLY ate ice cream + BOTH = 18 + 10 = 28.
Has anyone another strategic approach to solve this PS question? Regards!
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50 children attended a carnival where cotton candy
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Jay@ManhattanReview
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This is perfect.AAPL wrote:50 children attended a carnival where cotton candy and ice cream were sold. If 14 children ate only cotton candy, 18 children ate only ice cream, and 8 children had neither cotton candy nor ice cream, how many children ate ice cream?
A. 18
B. 20
C. 24
D. 28
E. 32
The OA is D.
This is an approach to solving this question (Double Matrix Method),
1. 14 children only cotton candy, 18 only ice cream, and 8 children no cotton candy and ice cream.
2. Only one left category: both ate cotton candy and ice cream, which is 50 - 14 - 18 - 8 = 10.
3. Thus, children who ate ice cream = children ONLY ate ice cream + BOTH = 18 + 10 = 28.
Has anyone another strategic approach to solve this PS question? Regards!
-Jay
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Shahrukh_mbabreakspace
- Senior | Next Rank: 100 Posts
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Let A be children eating Candy and B be children eating Ice cream
Then A union B is children eating atleast one thing
We know,
AUB= A+B-(A intersection B)= Only A+ Only B +(A intersection B)
Now, A union B= 50- 8= 42
42= 14 + 18 + x
x=10
So, total people who eat ice cream= 18+10= 28
Then A union B is children eating atleast one thing
We know,
AUB= A+B-(A intersection B)= Only A+ Only B +(A intersection B)
Now, A union B= 50- 8= 42
42= 14 + 18 + x
x=10
So, total people who eat ice cream= 18+10= 28
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Scott@TargetTestPrep
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We can create the following equation:AAPL wrote:50 children attended a carnival where cotton candy and ice cream were sold. If 14 children ate only cotton candy, 18 children ate only ice cream, and 8 children had neither cotton candy nor ice cream, how many children ate ice cream?
A. 18
B. 20
C. 24
D. 28
E. 32
total children = # ate ice cream only + # ate cotton candy only + # ate both + # ate neither
50 = 18 + 14 + b + 8
50 = b + 40
10 = b
Since 10 children ate both ice cream and cotton candy, we add these 10 to the 18 children who ate only ice cream to get 10 + 18 = 28 children who ate ice cream.
Answer: D
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