What is the lowest positive integer that is divisible by each of the even integers between 1 and 10, inclusive?
A. 60
B. 100
C. 120
D. 160
E. 240
The OA is the option C.
How can I find the correct answer here? Could anyone give me a good approach? Thanks.
What is the lowest positive integer that is divisible by
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Hi VJesus12,
We're asked for the SMALLEST positive integer that is divisible by each of the EVEN integers between 1 and 10, inclusive. This question can be solved rather easily by TESTing THE ANSWERS. Since we're asked for the SMALLEST number, we should start with Answer A and then work our way 'up' until we find the one that matches...
Answer A: 60.... is 60 divisible by 2, 4, 6, 8 and 10.... NO, it's not divisible by 8.
Answer A: 100.... is 100 divisible by 2, 4, 6, 8 and 10.... NO, it's not divisible by 6 or 8.
Answer A: 120.... is 120 divisible by 2, 4, 6, 8 and 10.... YES, it's divisible by all the values (re: 2x60, 4x30, 6x20, 8x15, 10x12).
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
We're asked for the SMALLEST positive integer that is divisible by each of the EVEN integers between 1 and 10, inclusive. This question can be solved rather easily by TESTing THE ANSWERS. Since we're asked for the SMALLEST number, we should start with Answer A and then work our way 'up' until we find the one that matches...
Answer A: 60.... is 60 divisible by 2, 4, 6, 8 and 10.... NO, it's not divisible by 8.
Answer A: 100.... is 100 divisible by 2, 4, 6, 8 and 10.... NO, it's not divisible by 6 or 8.
Answer A: 120.... is 120 divisible by 2, 4, 6, 8 and 10.... YES, it's divisible by all the values (re: 2x60, 4x30, 6x20, 8x15, 10x12).
Final Answer: C
GMAT assassins aren't born, they're made,
Rich
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We need to determine the smallest number that is divisible by the following:VJesus12 wrote:What is the lowest positive integer that is divisible by each of the even integers between 1 and 10, inclusive?
A. 60
B. 100
C. 120
D. 160
E. 240
2, 4, 6, 8, and 10
That is, we need to find the least common multiple (LCM) of 2, 4, 6, 8, and 10:
In prime factorization form, we have:
2, 2^2, 2 x 3, 2^3, 2 x 5
So the LCM is 2^3 x 3 x 5 = 8 x 15 = 120.
Answer: C
Jeffrey Miller
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