A, B, C are three consecutive positive integers (A>B>C). What is the value of the expression 2A +B +3C?
A. 6A+7.
B. 5A+1.
C. 5A-1.
D. 6A-5.
E. 6A-7.
The OA is the option E.
Why is E the correct answer? I got the option A. Could anyone help me here? Please. Thanks in advance.
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A, B, C are three consecutive positive integers (A>B>C
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Let A=3, B=2 and C=1.M7MBA wrote:A, B, C are three consecutive positive integers (A>B>C). What is the value of the expression 2A +B +3C?
A. 6A+7.
B. 5A+1.
C. 5A-1.
D. 6A-5.
E. 6A-7.
2A + B + 3C = (2*3) + 2 + (3*1) = 11.
Now plug A=3 into the answers to see which yields the value in blue.
Only E works:
6A-7 = (6*3) - 7 = 18 -7 = 11.
The correct answer is E.
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Hi All,
We're told that A, B, C are three consecutive positive integers and A > B > C. We're asked for the value of the expression (2A +B +3C). This question can be solved rather easily by TESTing VALUES (as Mitch has shown). You could also approach it Algebraically.
Since the three variables are CONSECUTIVE INTEGERS and A > B > C, we can write all three variables in terms of A...
A = A
B = A-1
C = A-2
Thus, the value of 2A + B + 3C can be written as...
2A + (A-1) + 3(A-2) =
2A + A - 1 + 3A - 6 =
6A - 7
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
We're told that A, B, C are three consecutive positive integers and A > B > C. We're asked for the value of the expression (2A +B +3C). This question can be solved rather easily by TESTing VALUES (as Mitch has shown). You could also approach it Algebraically.
Since the three variables are CONSECUTIVE INTEGERS and A > B > C, we can write all three variables in terms of A...
A = A
B = A-1
C = A-2
Thus, the value of 2A + B + 3C can be written as...
2A + (A-1) + 3(A-2) =
2A + A - 1 + 3A - 6 =
6A - 7
Final Answer: E
GMAT assassins aren't born, they're made,
Rich
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Scott@TargetTestPrep
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M7MBA wrote:A, B, C are three consecutive positive integers (A>B>C). What is the value of the expression 2A +B +3C?
A. 6A+7.
B. 5A+1.
C. 5A-1.
D. 6A-5.
E. 6A-7.
Since the integers A, B, and C are consecutive integers (with A > B > C) and we see that the answer choices are in terms of A, we can say B = A - 1 and C = A - 2. Thus:
2A + B + 3C = 2A + A - 1 + 3(A - 2) = 3A - 1 + 3A - 6 = 6A - 7
Answer: E
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