A man traveled a distance of 61 km in 9 hrs. He traveled partly on foot at the rate of 4 km/hr and partly on bicycle at 9 km/hr. The distance traveled on foot (in km) is
A 14
B 15
C 16
D 17
E 18
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vaibhav101
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We can PLUG IN THE ANSWERS, which represent the distance traveled at 4 kph.vaibhav101 wrote:A man traveled a distance of 61 km in 9 hrs. He traveled partly on foot at the rate of 4 km/hr and partly on bicycle at 9 km/hr. The distance traveled on foot (in km) is
A 14
B 15
C 16
D 17
E 18
Since all of the values in the problem are INTEGERS, the correct answer is almost certain to be a multiple of 4.
Of the 5 options, only C is a multiple of 4.
When the correct answer is plugged in, the total time = 9 hours.
C: 16 kilometers traveled at 4 kph, implying that the distance traveled at 9 kph = 61-16 = 45 kilometers
Time to travel 16 kilometers at 4 kph = d/r = 16/4 = 4 hours.
Time to travel 45 kilometers at 9 kph = d/r = 45/9 = 5 hours.
Total time = 4+5 = 9 hours.
Success!
The correct answer is C.
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Scott@TargetTestPrep
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We can let x = the number of hours on foo;, thus, (9 - x) = the number of hours on bicycle. We can create the equation:vaibhav101 wrote:A man traveled a distance of 61 km in 9 hrs. He traveled partly on foot at the rate of 4 km/hr and partly on bicycle at 9 km/hr. The distance traveled on foot (in km) is
A 14
B 15
C 16
D 17
E 18
4x + 9(9 - x) = 61
4x + 81 - 9x = 61
-5x = -20
x = 4
Thus, the distance on foot is 4 x 4 = 16 km.
Answer: C
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