If f(x) = x^2 - x + 1, is f(p)>f(q)?

This topic has expert replies
User avatar
Elite Legendary Member
Posts: 3991
Joined: Fri Jul 24, 2015 2:28 am
Location: Las Vegas, USA
Thanked: 19 times
Followed by:37 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

[GMAT math practice question] 5.31

If f(x) = x^2 - x + 1, is f(p)>f(q)?

1) p<q
2) p^2>q^2

User avatar
Elite Legendary Member
Posts: 3991
Joined: Fri Jul 24, 2015 2:28 am
Location: Las Vegas, USA
Thanked: 19 times
Followed by:37 members

by Max@Math Revolution » Mon Jun 04, 2018 9:43 am

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.
The first step of the VA (Variable Approach) method is to modify the original condition and the question. We then recheck the question.
Modifying the question:
f(p) > f(q)
=> f(p) - f(q) > 0
=> ( p^2 - p + 1 ) - ( q^2 - q + 1 ) > 0
=> ( p^2 - q^2 ) - ( p - q ) > 0
=> ( p + q )( p - q ) - ( p - q ) > 0
=> ( p + q - 1 )( p - q ) > 0
Since we have 2 variables (p and q) and 0 equations, C is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.
Conditions 1) & 2):
Condition 2) tells us that p^2 - q^2 = (p + q)(p - q) > 0. Since p - q < 0 by condition 1), we must have p + q < 0. It follows that p + q - 1 < 0, and
f(p) - f(q) = (p + q - 1)(p - q) > 0.
So, f(p) > f(q), and both conditions are sufficient, when taken together.
Therefore, C is the answer.