Is i>j?

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Is i>j?

by VJesus12 » Tue Mar 27, 2018 2:44 am
Is i>j?

1) k^2j>ki
2) j^2k>ji

The OA is the option E.

I don't know how to prove that the correct answer is the option E. May any expert give me some help? <i class="em em-sob"></i>

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by GMATGuruNY » Tue Mar 27, 2018 5:39 am
VJesus12 wrote:Is i>j?

1) k²j > ki
2) j²k > ji
Statement 1:
Case 1: k=1, j=2 and i=1, with the result that k²j=2 and ki=1
In this case, i < j, so the answer to the question stem is NO.
Case 2: k=-1, j=-2 and i=3, with the result that k²j=-2 and ki=-3
In this case, i > j, so the answer to the question stem is YES.
Since the answer is NO in Case 1 but YES in Case 2, INSUFFICIENT.

Statement 2:
Case 1: k=1, j=2 and i=1, with the result that j²k=4 and ji=2
In this case, i < j, so the answer to the question stem is NO.
Case 2: k=-1, j=-2 and i=3, with the result that j²k=-4 and ji=-6
In this case, i > j, so the answer to the question stem is YES.
Since the answer is NO in Case 1 but YES in Case 2, INSUFFICIENT.

Statements combined:
Cases 1 and 2 satisfy both statements.
Since the answer is NO in Case 1 but YES in Case 2, INSUFFICIENT.

The correct answer is E.
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