Problem Solving

A cylindrical bucket, with height 10 and radius r, is 3/4 filled with water. A boy is dropping marbles with volume r/10 into the bucket at a rate of 12 per minute. How many seconds will it take before water overflows from the bucket?

$$A.\ 2.1r\pi$$
$$B.\ 25r\pi$$
$$C.\ 125r\pi$$
$$D.\ 300r\pi$$
$$E.\ 375r\pi$$

The OA is C.

I know that the volume of cylinder=Ï€*r^2*h=Ï€r^2*10

Then?

Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks.

swerve wrote:A cylindrical bucket, with height 10 and radius r, is 3/4 filled with water. A boy is dropping marbles with volume r/10 into the bucket at a rate of 12 per minute. How many seconds will it take before water overflows from the bucket?

$$A.\ 2.1r\pi$$
$$B.\ 25r\pi$$
$$C.\ 125r\pi$$
$$D.\ 300r\pi$$
$$E.\ 375r\pi$$

The OA is C.

I know that the volume of cylinder=Ï€*r^2*h=Ï€r^2*10

Then?

Please, can any expert explain this PS question for me? I tried to solve it but I can't get the correct answer. I need your help. Thanks.

Where did you get this question from? The question and answers are not correct.

This is how you want to structure your answer:

(1) What is the volume of the bucket: Vb = 10Ï€r^2 as you say above.
(2) What is the empty volume in bucket: (1/4)*Vb = 2.5Ï€r^2
(3) What is the volume of a marble: Vm = (4/3)Ï€(r/10)^3 = (4Ï€r^3)/3000
(4) How many marbles need to be dropped in the bucket such that it will push the water up to the top: Empty Volume / Volume of Marble = (2.5Ï€r^2)/((4Ï€r^3)/3000) = 7500/4r = 1875/r
(5) How often is a marble dropped into the bucket? 12 go in a minute so that is 1 every 5 seconds
(6) Time for water to be at top = # of required marbles * how often a marble is dropped in = (1875/r)*5 = 9375/r seconds
(7) Then getting technical the water won't overflow until you drop in 1 more marble so you need to add 5 seconds to the time above: 9375/r + 5 seconds