If Robert can assemble a model car in 30 minutes and Craig can assemble the same model car in 20 minutes, how long would it take tehm, working together, to assemble the model car?
A. 12 minutes
B. 13 minutes
C. 14 minutes
D. 15 minutes
E. 16 minutes
The OA is A.
I'm confused by this PS question. Experts, any suggestion? Thanks in advance.
How can I determine the rate of each one? Can I say that the model car has a n number of pieces?
If Robert can assemble a model car in 30 minutes...
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The easiest approach on this question is to use the combined work equation $$\frac{1}{A}+\frac{1}{B}=\frac{1}{A and B}$$ Where A and B are the time it would take each person (or machine, pump, printer, etc. depending on the question) to finish a job alone, and A and B is the time it would take both to finish the same job together.
In this problem, A will be the time it takes Robert to assemble the model car alone, B will be the time it takes Craig to assemble the model car alone, and A and B will be the time it takes the two of them to assemble the model car together. Plugging in the information from our equation gives: $$\frac{1}{20}+\frac{1}{30}=\frac{1}{A\ and\ B}$$ Then solving for A and B gives $$\frac{3}{60}+\frac{2}{60}=\frac{1}{A\ and\ B}$$ $$\frac{5}{60}=\frac{1}{A\ and\ B}$$ $$5\left(A\ and\ B\right)=60$$ $$A\ and\ B=12$$ So Robert and Craig can assemble the model car together in 12 minutes, and the correct answer is A.
In this problem, A will be the time it takes Robert to assemble the model car alone, B will be the time it takes Craig to assemble the model car alone, and A and B will be the time it takes the two of them to assemble the model car together. Plugging in the information from our equation gives: $$\frac{1}{20}+\frac{1}{30}=\frac{1}{A\ and\ B}$$ Then solving for A and B gives $$\frac{3}{60}+\frac{2}{60}=\frac{1}{A\ and\ B}$$ $$\frac{5}{60}=\frac{1}{A\ and\ B}$$ $$5\left(A\ and\ B\right)=60$$ $$A\ and\ B=12$$ So Robert and Craig can assemble the model car together in 12 minutes, and the correct answer is A.
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If 'A' is the amount of time for one entity to complete a job, and 'B' is the amount of time for a second entity to complete the same job, then the time for the two to complete the job together is (A*B)/(A + B)LUANDATO wrote:If Robert can assemble a model car in 30 minutes and Craig can assemble the same model car in 20 minutes, how long would it take tehm, working together, to assemble the model car?
A. 12 minutes
B. 13 minutes
C. 14 minutes
D. 15 minutes
E. 16 minutes
The OA is A.
I'm confused by this PS question. Experts, any suggestion? Thanks in advance.
How can I determine the rate of each one? Can I say that the model car has a n number of pieces?
A= 30 minutes
B= 20 minutes
A*B/(A+B) = 30*20/(30+20) = 30*20/50 = 30*2/5 = 60/5 = 12. The answer is A
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LUANDATO wrote:If Robert can assemble a model car in 30 minutes and Craig can assemble the same model car in 20 minutes, how long would it take tehm, working together, to assemble the model car?
A. 12 minutes
B. 13 minutes
C. 14 minutes
D. 15 minutes
E. 16 minutes
The OA is A.
I'm confused by this PS question. Experts, any suggestion? Thanks in advance.
How can I determine the rate of each one? Can I say that the model car has a n number of pieces?
Note that the formula (A*B)/(A + B) = T is really the same one that Erika used. If the first rate is 1/A and the second rate is 1/B the combined rate is 1/A + 1/B, which comes out to (A+B)/A*B. Because rate and time have a reciprocal relationship, a rate of (A+B)/A*B is equivalent to a time of A*B/(A + B)
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BTGmoderatorLU wrote:If Robert can assemble a model car in 30 minutes and Craig can assemble the same model car in 20 minutes, how long would it take tehm, working together, to assemble the model car?
A. 12 minutes
B. 13 minutes
C. 14 minutes
D. 15 minutes
E. 16 minutes
The combined rate of Robert and Craig is 1/20 + 1/30 = 3/60 + 2/60 = 5/60. We can interpret this rate as "They can assemble 5 model cars in 60 minutes." Since time is the reciprocal of rate, it would take them 60/5 = 12 minutes to complete one car.
Answer: A