A computer appliance dealer bought a computer at a wholesale price of $500 and then sold it at a 20 percent discount off the suggested retail price. If the dealer made a 12 percent profit on the wholesale price, what was the suggested retail price of the computer?
A) $560
B) $580
C) $660
D) $700
E) $730
Please show me the best solution in this?
OA D
A computer appliance dealer bought a computer
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Start by identifying gkey facts separately:
1) Selling price = 20% off the Retail price (R) is the same as 80% of R = 0.8R
2) Profit = 12% of 500 = 0.12 *500 = 60
3) Profit = Selling price - Purchase price
So, substituting all facts into equation (3) gives
60 = 0.8R - 500
Rearranging gives
0.8R = 560
x10 gives
8R = 5600
/8 gives
R = 700
ANSWER = D
1) Selling price = 20% off the Retail price (R) is the same as 80% of R = 0.8R
2) Profit = 12% of 500 = 0.12 *500 = 60
3) Profit = Selling price - Purchase price
So, substituting all facts into equation (3) gives
60 = 0.8R - 500
Rearranging gives
0.8R = 560
x10 gives
8R = 5600
/8 gives
R = 700
ANSWER = D
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Hello lheiannie07.
Let's take a look at your question.
A computer appliance dealer bought a computer at a wholesale price of $500 and then sold it at a 20 percent discount off the suggested retail price. If the dealer made a 12 percent profit on the wholesale price, it implies that he sold the computer at a price of $$500+500\cdot12\%=500+500\cdot0.12=500+60=560\ \text{dollars}.$$ Now, let x the suggested price, then $$x-20\%\cdot x=80\%\cdot x=0.8\cdot x=560\ \Leftrightarrow\ x=\frac{560}{0.8}=700\ \text{dollars}.$$ Hence, the correct answer is the option [spoiler]D=$700[/spoiler].
I hope this explanation may help you.
I'm available if you'd like a follow-up.
Regards.
Let's take a look at your question.
A computer appliance dealer bought a computer at a wholesale price of $500 and then sold it at a 20 percent discount off the suggested retail price. If the dealer made a 12 percent profit on the wholesale price, it implies that he sold the computer at a price of $$500+500\cdot12\%=500+500\cdot0.12=500+60=560\ \text{dollars}.$$ Now, let x the suggested price, then $$x-20\%\cdot x=80\%\cdot x=0.8\cdot x=560\ \Leftrightarrow\ x=\frac{560}{0.8}=700\ \text{dollars}.$$ Hence, the correct answer is the option [spoiler]D=$700[/spoiler].
I hope this explanation may help you.
I'm available if you'd like a follow-up.
Regards.
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Profit = 12% of the $500 wholesale price = (12/100)(500) = 60.lheiannie07 wrote:A computer appliance dealer bought a computer at a wholesale price of $500 and then sold it at a 20 percent discount off the suggested retail price. If the dealer made a 12 percent profit on the wholesale price, what was the suggested retail price of the computer?
A) $560
B) $580
C) $660
D) $700
E) $730
Thus:
Selling price = (wholesale price) + (profit) = 500+60 = 560.
We can PLUG IN THE ANSWERS, which represent the retail price.
When the retail price is reduced by 20%, the result will be the $560 selling price.
Answer choice D: 700
700 - (20% of 700) = 700 - 140 = 560.
Success!
The correct answer is D.
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We can let r = the suggested retail price of the computer.lheiannie07 wrote:A computer appliance dealer bought a computer at a wholesale price of $500 and then sold it at a 20 percent discount off the suggested retail price. If the dealer made a 12 percent profit on the wholesale price, what was the suggested retail price of the computer?
A) $560
B) $580
C) $660
D) $700
E) $730
Since the dealer sold the computer at a 20% discount off the suggested retail price, the dealer sold the computer for 0.8r. Since the dealer made a 12% profit, we can create the following equation to determine r:
revenue - cost = 0.12(cost)
0.8r - 500 = 0.12(500)
0.8r - 500 = 60
0.8r = 560
r = 560/0.8 = 700
Answer:D
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