Problem Solving

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

OA is D

OA says D but I solved and got E can an Expert shoe some solutions? Thanks

Local kennel has cats and dogs in the ratio of 5:6. If there are 18 fewer cats than dogs, how many dogs are in the kennel?

A. 60
B. 74
C. 98
D. 108
E. 132

OA is D

OA says D but I solved and got E can an Expert shoe some solutions? Thanks

Hi Roland2rule,
Let's take a look at your question.

If C denotes cats and D denotes dogs, then,
$$\frac{C}{D}=\frac{5}{6}$$
$$6C=5D...(i)$$

If there are 18 fewer cats then dogs, we can write it as,
$$C=D-18$$

Substitute C in eq(i),
$$6\left(D-18\right)=5D$$
$$6D-108=5D$$
$$6D-5D=108$$
$$D=108$$

Therefore, Option D is correct.

Hope it helps.
I am available if you'd like any follow up.