The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).
Good one...
Probability - breaking the jar ?
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- arora007
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- nithi_mystics
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b) X/Y
probability of pulling a black ball out of a glass jar and breaking the jar = probability of pulling a black ball out of a glass jar * probability of breaking the jar
1/y = 1/x * probability of breaking the jar
==> probability of breaking the jar = x/y
probability of pulling a black ball out of a glass jar and breaking the jar = probability of pulling a black ball out of a glass jar * probability of breaking the jar
1/y = 1/x * probability of breaking the jar
==> probability of breaking the jar = x/y
Thanks
Nithi
Nithi
- Gurpinder
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to get the probability of something AND something happening you multiply the two probabilitiesarora007 wrote:The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).
Good one...
so that means that 1/x * ______ = 1/y so just divide 1/x / 1/y which equals to x/y
so the answer is B
- arora007
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both of u deserve a 51. God bless!!
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- Bill@VeritasPrep
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Yup. The keyword here is AND: black ball AND jar breaks. Nicely done.nithi_mystics wrote:b) X/Y
probability of pulling a black ball out of a glass jar and breaking the jar = probability of pulling a black ball out of a glass jar * probability of breaking the jar
1/y = 1/x * probability of breaking the jar
==> probability of breaking the jar = x/y
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- Jeff@TargetTestPrep
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We can let the probability of breaking the jar = p; thus:arora007 wrote:The probability of pulling a black ball out of a glass jar is 1/X. The probability of pulling a black ball out of a glass jar and breaking the jar is 1/Y. What is the probability of breaking the jar?
a) 1/(XY).
b) X/Y.
c) Y/X.
d) 1/(X+Y).
e) 1/(X-Y).
(1/X)p = (1/Y)
p = (1/Y)/(1/X)
p = X/Y
Answer: B
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