Problem Solving

Given a spinner with four sections of equal size labeled A, B, C, and D, what is the probability of NOT getting an A after spinning the spinner two times?

A. 15/16
B. 9/16
C. 1/2
D. 1/4
E. 1/8

The OA is B.

How can I calculate this probability? Experts, can you give me an explanation here? Thanks.

Given a spinner with four sections of equal size labeled A, B, C, and D, what is the probability of NOT getting an A after spinning the spinner two times?

A. 15/16
B. 9/16
C. 1/2
D. 1/4
E. 1/8

The OA is B.

How can I calculate this probability? Experts, can you give me an explanation here? Thanks.

Hi M7MBA,
Let's take a look at your question.

Probability of Not Getting an A after spinning the spinner two times can be calculated as:
$$P\left(\text{Not getting an A}\right)\times P\left(\text{Not getting an A}\right)$$
$$=\frac{3}{4}\times\frac{3}{4}=\frac{9}{16}$$

Therefore, option B is correct.

Hope it helps.
I am available if you'd like any follow up.