The price of a book, after it was reduced by 1/3, is B dollars. What was the price of the book, in dollars, before the reduction?
a. 2b/3
b. 3b/4
c. 6b/5
d. 4b/3
e. 3b/2
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aim-wsc
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Let P be the price of the bookpj94z wrote:The price of a book, after it was reduced by 1/3, is B dollars. What was the price of the book, in dollars, before the reduction?
a. 2b/3
b. 3b/4
c. 6b/5
d. 4b/3
e. 3b/2
reduced price = P- P(1/3)
=P * ( 1-1/3 )
= P ( 2/3 )
therefore P= (3/2) reduced price.
Answer: E
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gabriel
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...when u reduce a qty by 1/3 ... what is left is 2/3 of the original qty...pj94z wrote:The price of a book, after it was reduced by 1/3, is B dollars. What was the price of the book, in dollars, before the reduction?
a. 2b/3
b. 3b/4
c. 6b/5
d. 4b/3
e. 3b/2
so.. let x be the original price ... therefore 2/3 x = b... therefore x = 3b/2... E..
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Cybermusings
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The price of a book, after it was reduced by 1/3, is B dollars. What was the price of the book, in dollars, before the reduction?
a. 2b/3
b. 3b/4
c. 6b/5
d. 4b/3
e. 3b/2
x - 1/3 x = b
2/3x = b
Therefore x = 3b/2
a. 2b/3
b. 3b/4
c. 6b/5
d. 4b/3
e. 3b/2
x - 1/3 x = b
2/3x = b
Therefore x = 3b/2
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BTGmoderatorRO
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Let the initial price of the book $x
If we reduce x by $$\frac{1}{3}$$
x- $$\frac{1}{3x}$$
we have $$\frac{2}{3}$$ of x left
i.e
$$\frac{2}{3}$$ of x = $B
$$\frac{2x}{3}$$ = B
2x =3B
x = $$\frac{3B}{2}$$
i.e the price of the book before the reduction is $$\frac{3B}{2}$$ .
If we reduce x by $$\frac{1}{3}$$
x- $$\frac{1}{3x}$$
we have $$\frac{2}{3}$$ of x left
i.e
$$\frac{2}{3}$$ of x = $B
$$\frac{2x}{3}$$ = B
2x =3B
x = $$\frac{3B}{2}$$
i.e the price of the book before the reduction is $$\frac{3B}{2}$$ .
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Scott@TargetTestPrep
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We can create the equation:pj94z wrote:The price of a book, after it was reduced by 1/3, is B dollars. What was the price of the book, in dollars, before the reduction?
a. 2b/3
b. 3b/4
c. 6b/5
d. 4b/3
e. 3b/2
D * 2/3 = B
2D = 3B
D = 3B/2
Answer: E
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