A clown blows up a spherical balloon such that its volume increases at a constant rate. I takes 3 seconds for the radius of the balloon to increase from 1 inch to 2 inches. How many seconds does it take for the radius of the balloon to increase from 3 inches to 5 inches?
NOTE: The volume of a single sphere is 4/3*Ï€r^3.
A. 6
B. 9
C. 24
D. 30
E. 42
The OA is E.
Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
A clown blows up a spherical balloon such that its...
This topic has expert replies
- EconomistGMATTutor
- GMAT Instructor
- Posts: 555
- Joined: Wed Oct 04, 2017 4:18 pm
- Thanked: 180 times
- Followed by:12 members
Hello AAPL.
This is an interesting question. I will try to explain how to solve it.
It takes 3 seconds for the radius of the balloon to increase from 1 inch to 2 inches, so the volume increases from $$V_1=\frac{4\pi\left(1\right)^3}{3}=\frac{4\pi}{3}\ \ \ to\ \ V_2=\frac{4\pi\left(2\right)^3}{3}=\frac{32\pi}{3}$$ in 3 seconds.
We know that the volume increases at a constant rate. So it increase at $$\frac{28\pi}{3}\ each\ 3\ \sec onds,\ or\ \frac{28\pi}{9}\ per\ \sec ond.$$ Now, $$V_3=\frac{4\pi\left(3\right)^3}{3}=36\pi\ \ and\ V_5=\frac{4\pi\left(5\right)^3}{3}=\frac{500\pi}{3}.$$ So $$V_5-V_4=\frac{500\pi}{3}-36\pi=\frac{392\pi}{3}.$$ Finally, $$\frac{\frac{392\pi}{3}}{\frac{28\pi}{9}}=\frac{3528\pi}{84\pi}=42\ .$$ It implies that it takes 42 seconds to increase the radius from 3 inches to 5 inches. The correct answer is E .
I hope it can help you.
Feel free to ask me again if you have a doubt.
Regards.
This is an interesting question. I will try to explain how to solve it.
It takes 3 seconds for the radius of the balloon to increase from 1 inch to 2 inches, so the volume increases from $$V_1=\frac{4\pi\left(1\right)^3}{3}=\frac{4\pi}{3}\ \ \ to\ \ V_2=\frac{4\pi\left(2\right)^3}{3}=\frac{32\pi}{3}$$ in 3 seconds.
We know that the volume increases at a constant rate. So it increase at $$\frac{28\pi}{3}\ each\ 3\ \sec onds,\ or\ \frac{28\pi}{9}\ per\ \sec ond.$$ Now, $$V_3=\frac{4\pi\left(3\right)^3}{3}=36\pi\ \ and\ V_5=\frac{4\pi\left(5\right)^3}{3}=\frac{500\pi}{3}.$$ So $$V_5-V_4=\frac{500\pi}{3}-36\pi=\frac{392\pi}{3}.$$ Finally, $$\frac{\frac{392\pi}{3}}{\frac{28\pi}{9}}=\frac{3528\pi}{84\pi}=42\ .$$ It implies that it takes 42 seconds to increase the radius from 3 inches to 5 inches. The correct answer is E .
I hope it can help you.
Feel free to ask me again if you have a doubt.
Regards.
GMAT Prep From The Economist
We offer 70+ point score improvement money back guarantee.
Our average student improves 98 points.
We offer 70+ point score improvement money back guarantee.
Our average student improves 98 points.
GMAT/MBA Expert
- Scott@TargetTestPrep
- GMAT Instructor
- Posts: 7249
- Joined: Sat Apr 25, 2015 10:56 am
- Location: Los Angeles, CA
- Thanked: 43 times
- Followed by:29 members
If the radius of the balloon is 1 inch, the volume of the balloon is 4/3*π(1)^3 = 4π/3. If the radius is 2 inches, the volume is 4/3*π(2)^3 = 32π/3. Since it takes 3 seconds for the radius to increase from 1 inch to 2 inches, the rate at which the volume is increasing is (32π/3 - 4π/3)/3 = 28π/9 cubic inches per second.AAPL wrote:A clown blows up a spherical balloon such that its volume increases at a constant rate. I takes 3 seconds for the radius of the balloon to increase from 1 inch to 2 inches. How many seconds does it take for the radius of the balloon to increase from 3 inches to 5 inches?
NOTE: The volume of a single sphere is 4/3*Ï€r^3.
A. 6
B. 9
C. 24
D. 30
E. 42
The OA is E.
Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
Now, if the radius of the balloon is 3 inches, the volume of the balloon is 4/3*π(3)^3 = 108π/3. If the radius is 5 inches, the volume is 4/3*π(5)^3 = 500π/3. Since the rate at which the volume is increasing is 28π/9 cubic inches per second, then it takes (500π/3 - 108π/3)/(28π/9) = 392π/3 * 9/(28π) = 14 * 3 = 42 seconds to increase the radius of the balloon from 3 inches to 5 inches.
Answer: E
Scott Woodbury-Stewart
Founder and CEO
[email protected]
See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews