Points A, B, C, D lie in this order on the circumference of a circle. Minor arc AC is 160°, and minor arc BD is 140°. If B bisects minor arc AC, then what is the measure of minor arc AD?
A. 80°
B. 120°
C. 140°
D. 160°
E. 220°
The OA is C.
Please, can any expert assist me with this PS question? I don't have it clear and I appreciate if any explain it for me. Thanks.
Points A, B, C, D lie in this order on the circumference...
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- EconomistGMATTutor
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Hello AAPL.
If you look at the image and fill it with the data, you will get the correct answer.
The measure of AC=160º and B bisects this arc, so AB=80º and BC=80.
As BD=140º and BC=80º, then CD=60º.
So, the meause of AD is AC+CD=160º+60º=220º.
Then, the minor arc AD is 360º-220º=140º.
So, the correct answer is C .
I hope this may help you.
I'm available if you'd like a follow up.
Regards.
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