In how many ways can 6 people be seated at a round table if one of those seated cannot sit next to 2 of the other 5?
a) 720
b) 120
c) 108
d) 84
e) 48
combination,table, 700+, manhattan
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I believe that the following reflects the intent of the problem:
1. Place someone in the circle.
2. Count the number of ways to arrange the REMAINING people.
After A is placed in the circle:
Number of options for the seat to the left of A = 3. (Of the 5 remaining people, anyone but B or C.)
Number of options for the seat to the right of A = 2. (Of the 4 remaining people, anyone but B or C.)
Number of ways to arrange the remaining 3 people = 3! = 6.
To combine these options, we multiply:
3*2*6 = 36.
The correct number of arrangements is not among the answer choices.
What is the source of this problem?
To count circular arrangements:In how many ways can 6 people A, B, C, D, E and F be seated at a round table if A cannot sit next to B or C?
a) 720
b) 120
c) 108
d) 84
e) 48
1. Place someone in the circle.
2. Count the number of ways to arrange the REMAINING people.
After A is placed in the circle:
Number of options for the seat to the left of A = 3. (Of the 5 remaining people, anyone but B or C.)
Number of options for the seat to the right of A = 2. (Of the 4 remaining people, anyone but B or C.)
Number of ways to arrange the remaining 3 people = 3! = 6.
To combine these options, we multiply:
3*2*6 = 36.
The correct number of arrangements is not among the answer choices.
What is the source of this problem?
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I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
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- GMATGuruNY
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Given the answer choices, I suspect that the prompt is intended to ask the following:
1. Place someone in the circle.
2. Count the number of ways to arrange the remaining people.
Good arrangements = (total possible arrangements) - (bad arrangements).
Total possible arrangements:
After A has been seated at the table, the number of ways to arrange the remaining 5 people = 5! = 120.
Bad arrangements:
In a bad arrangement, A, B and C sit in 3 adjacent seats, with A between B and C.
After A has been seated:
Number of options for the seat to the left of A = 2. (B or C.)
Number of options for the seat to the right of A = 1. (Must be B or C, whoever is not seated to the left of A.)
Number of ways to arrange the remaining 3 people = 3! = 6.
To combine these options, we multiply:
2*1*6 = 12.
Thus:
Good arrangements = 120 - 12 = 108.
The correct answer is C.
The problem as written seems poorly worded.
As noted in my post directly above, to count circular arrangements:In how many ways can 6 people A, B, C, D, E and F be seated at a round table if A, B and C cannot sit in 3 adjacent seats such that A is between B and C?
a) 720
b) 120
c) 108
d) 84
e) 48
1. Place someone in the circle.
2. Count the number of ways to arrange the remaining people.
Good arrangements = (total possible arrangements) - (bad arrangements).
Total possible arrangements:
After A has been seated at the table, the number of ways to arrange the remaining 5 people = 5! = 120.
Bad arrangements:
In a bad arrangement, A, B and C sit in 3 adjacent seats, with A between B and C.
After A has been seated:
Number of options for the seat to the left of A = 2. (B or C.)
Number of options for the seat to the right of A = 1. (Must be B or C, whoever is not seated to the left of A.)
Number of ways to arrange the remaining 3 people = 3! = 6.
To combine these options, we multiply:
2*1*6 = 12.
Thus:
Good arrangements = 120 - 12 = 108.
The correct answer is C.
The problem as written seems poorly worded.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3