gmat prep q

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gmat prep q

by smallsorrow » Sat Sep 20, 2008 1:07 am
For the students in class A the range of their hights is r centimeters and the greatest hight is g centimenters. Class B´s range of hights is s centimeters and greatest hight is h centimeters. Is the least hight of the students in class A greater than that of class B?
1. r < s
2. g> h

OA follows.
Have I missed a formula?? I would not know how to solve this...

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by csandeepreddy » Sat Sep 20, 2008 9:29 am
My guess is E.

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by dragonxlam » Sat Sep 20, 2008 10:59 am
Well basically I think this is a good question to plug in the values.

The equations look something like this:

g-r = Lowest Height of kid in Group A
h-s = Lowest Height of kid in Group B

Looking at 1) r < s alone does not tell you anything since you don't know what g and h are to come to a conclusion.

Getting 2) g > h gives you more info and enables you to plug in some numbers.

g= 10
h=9

r=4
s=3

So Lowest height is 6 in group A but it is also the same in group B.

You can plug in more numbers so that group B is shorter so in this case the answer is E.

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by smallsorrow » Sun Sep 21, 2008 2:10 am
Guess what,
the OA is C. I picked E, too...

Anybody outthere who could explain in detail??

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by smallsorrow » Sun Sep 21, 2008 2:11 am
Guess what,
the OA is C. I picked E, too...

Anybody outthere who could explain in detail??

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Re: gmat prep q

by Ian Stewart » Sun Sep 21, 2008 6:28 am
smallsorrow wrote:For the students in class A the range of their hights is r centimeters and the greatest hight is g centimenters. Class B´s range of hights is s centimeters and greatest hight is h centimeters. Is the least hight of the students in class A greater than that of class B?
1. r < s
2. g> h

OA follows.
Have I missed a formula?? I would not know how to solve this...
dragonxiam- when you chose numbers here, you made r larger than s, when it should be smaller than s, which is why you've arrived at the wrong answer.

Neither statement is sufficient on its own- clearly we need to know about r, s, g and h here. Together we know:

s > r
g > h

These inequalities are in the same direction, so we can add them:

s+g > r+h
g-r > h-s

So we've shown that the smallest height in class A, which is g-r, is larger than the smallest height in class B, which is h-s. C.
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