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Can you solve this?

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Can you solve this?

by srican » Mon Jan 15, 2007 7:43 pm
A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?

(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

Total Game = 30 (based on 20 games played so far). I'm struggling with how to split it into 3/4 ratio.

Thanks
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by aim-wsc » Mon Jan 15, 2007 8:43 pm
I really have very limited knowledge of Basketball. :(

if we have 30 matches in total : 3/4th number would be 22.5 and since it is mentioned that it has to be at least 3/4 so we ll take 22.

That means team has to win 22 matches overall
Team already played two games and won 17 matches. Now all they need is 5 more wins.

least 5 wins that means at the most 5 losses they can afford.
:)

btw is a game consisted of 10 matches?
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by sumitkrishna » Tue Jan 16, 2007 9:59 pm
My logic is like this.

There are 10 games remaining to be played. Out of 30 games, 3/4th = 22.5. The question asks for winning at least this number. They have already won 17 games. If they win 5 more, they will win a total of 22 which is less than 3/4th of total. If they win 6 then they will have won at least 3/4th. Thus they can lose 4 at max.

So I would go with (D).
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by aim-wsc » Tue Jan 16, 2007 10:19 pm
oops yeah
you are right ..sumit

i missed that point.. silly

they have to win 23 matches...

so they still need 6 wins..
so
4 is right answer..

thanks.
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by telugupilla » Fri Feb 02, 2007 1:57 pm
yeah 4!!!
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re;

by BTGmoderatorRO » Sat Sep 16, 2017 6:43 pm
total games to be played = 30
(2/3) * 30= 20
win- 17
loss- 3
we have 10 games left to be played, and based on [(3/4 of 30)]=22.5
This means that 6 games out of the remaining 10 games must be win.
So, the team can lose 4 games and still maintain its 3/4 win rate target

Thus, option D which satisfy 4 is correct. Smile
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by Matt@VeritasPrep » Sun Sep 17, 2017 5:20 pm
17 + 3 = 20 games played

20 games played = (2/3) of all games, so 30 = all games

30 total games, and we want the team to finish with more than 22.5 wins, or with at least 23 wins.

To reach that record, the team must win AT LEAST 6 more games. There are 10 games left, so the team can lose AT MOST 4 more games.
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Re: Can you solve this?

by Scott@TargetTestPrep » Sat Feb 08, 2020 7:24 pm
srican wrote: ↑
Mon Jan 15, 2007 7:43 pm
 A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?

(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

Total Game = 30 (based on 20 games played so far). I'm struggling with how to split it into 3/4 ratio.

Thanks
Since 20 games (17 wins and 3 losses) represent 2/3 of the total games played, we can say:

(2/3)(total) = 20

Total = 30

Thus, there are 10 games left.

We need to determine how many games can be lost so that at least 3/4 of the games are won, or, in other words, so that at most 1/4 of the games are lost. We can let x = the number of games that can be lost, and we have:

(x + 3)/30 ≤ 1/4

4x + 12 ≤ 30

4x ≤ 18

x ≤ 4.5

Since x must be an integer, the largest integer less than or equal to 4.5 is 4.

Answer: D

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Re: Can you solve this?

by Brent@GMATPrepNow » Sun Feb 09, 2020 8:08 am
srican wrote: ↑
Mon Jan 15, 2007 7:43 pm
 A certain basketball team that has played 2/3 of its games has a record of 17 wins and 3 losses. What is the greatest number of the remaining games that the team can lose and still win at least 3/4 of all of its games?

(A) 7
(B) 6
(C) 5
(D) 4
(E) 3

Total Game = 30 (based on 20 games played so far). I'm struggling with how to split it into 3/4 ratio.

Thanks
Given:
The team has played 2/3 of its games. The team has played 20 games.
If 2/3 of the total number of games = 20, then the total number of games = 30.
This means that there are 10 games remaining.


We want the team to win at least 3/4 of its games.
3/4 of 30 = 22.5
So, in order to win at least 3/4 of the games, the team must win a total of 23 games or more.

The team has already won 17 games, so it needs to win at least 6 of the remaining 10 games.
Or we can say that the team can lose 4 games at most.

Answer = D

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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