Average/Median

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Average/Median

by beater » Wed Sep 17, 2008 12:06 pm
Tom, Jane, and Sue each purchased a new house. The average (arithmetic mean) price of the three houses was $120,000. What was the median price of the three houses?
(1) The price of Tom’s house was $110,000.
(2) The price of Jane’s house was $120,000.

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by mals24 » Wed Sep 17, 2008 1:06 pm
IMO B

St 1 says Tom's house = $110,000
Since we cannot find any information about the other two this st is INSUFF

St 2 says Jane's house = $120,000 = average.

Hence either all the three houses have the same value or one of them has a value higher than 120k and the other will have a value less than 120k making 120k the median.

For instance if Jane's house is 120,000 and say Tom's house is 120,001 then Sue's house will be 119,999 which is less than 120k

Hope you understood the working

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by lunarpower » Thu Sep 18, 2008 1:26 am
mals24 wrote:IMO B

St 1 says Tom's house = $110,000
Since we cannot find any information about the other two this st is INSUFF

St 2 says Jane's house = $120,000 = average.

Hence either all the three houses have the same value or one of them has a value higher than 120k and the other will have a value less than 120k making 120k the median.

For instance if Jane's house is 120,000 and say Tom's house is 120,001 then Sue's house will be 119,999 which is less than 120k

Hope you understood the working
right on.

remember, when you get a statement about the AVERAGE of a set, you should translate that statement into a statement about the SUM of the numbers in the set.

in this case, the average is 120,000. since there are three numbers in the set, the sum of the numbers is 120,000 x 3 = 360,000.

statement (1)
sum of the other 2 prices = 250,000
here are two ways to do this: 150,000 and 100,000 (in which case the 110,000 would be the median), or 125,000 and 125,000 (in which case one of the 125,000's would be the median).

statement (2)
covered perfectly in the above post.
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