tricky counting - Four women and three men must be seated

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Four women and three men must be seated in a row for a group photograph. If no two men can sit next to each other, in how many different ways can the seven people be seated?

A) 240
B) 480
C) 720
D) 1440
E) 5640

Answer: D

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Last edited by Brent@GMATPrepNow on Wed Apr 19, 2017 6:20 am, edited 1 time in total.
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by GMATGuruNY » Wed Apr 19, 2017 6:16 am
Brent@GMATPrepNow wrote:Four women and three men must be seated in a row for a group photograph. If no two men can sit next to each other, in how many different ways can the seven people be seated?

A) 240
B) 480
C) 720
D) 4880
E) 5640
Number of ways to arrange the four women = 4! = 24.

Once the 4 women have been arranged, the 3 men must be kept separated.
Thus, the 3 men may occupy any of the 5 empty slots below:
_W_W_W_W_

Number of options for the first man = 5. (Any of the 5 empty slots.)
Number of options for the second man = 4. (Any of the 4 remaining empty slots.)
Number of options for the third man = 3. (Any of the 3 remaining empty slots.)

To combine the options in blue, we multiply:
24*5*4*3 = 1440.

The correct answer is D.
Last edited by GMATGuruNY on Wed Apr 19, 2017 6:24 am, edited 1 time in total.
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by Brent@GMATPrepNow » Wed Apr 19, 2017 6:21 am
GMATGuruNY wrote:
Number of ways to arrange the four women = 4! = 24.

Once the 4 women have been arranged, the 3 men may occupy any of the 5 empty slots below:
_W_W_W_W_

Number of options for the first man = 5. (Any of the 5 empty slots.)
Number of options for the second man = 4. (Any of the 4 remaining empty slots.)
Number of options for the third man = 3. (Any of the 3 remaining empty slots.)

To combine the options in blue, we multiply:
24*5*4*3 = 1440.

The correct answer does not seem to be among the answer choices.
Good catch!
I've edited the answer choices.

Cheers,
Brent
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