If a = -0.3, which of the following is true?
A) a < a^2 < a^3
B) a < a^3 < a^2
C) av2 < a < a^3
D) av2 < a^3 < a
E) a^3 < a < a^2
OA: B
If a = -0.3, (OG160
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I fixed answer choices C and D to reflect the intent of the question.
a = -0.3
a² = (-0.3)(-0.3) = 0.09
a³ = (-0.3)(-0.3)(-0.3) = -0.027
If we order these values, we get: -0.3 < -0.027 < 0.09
In other words, a < a³ < a²
Answer: B
Cheers,
Brent
If a = -0.3, then:boomgoesthegmat wrote:If a = -0.3, which of the following is true?
A) a < a² < a³
B) a < a³ < a²
C) a² < a < a³
D) a² < a³ < a
E) a³ < a < a²
OA: B
a = -0.3
a² = (-0.3)(-0.3) = 0.09
a³ = (-0.3)(-0.3)(-0.3) = -0.027
If we order these values, we get: -0.3 < -0.027 < 0.09
In other words, a < a³ < a²
Answer: B
Cheers,
Brent
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Hi boomgoesthegmat,
For this question, it's important to remember WHY a number is bigger than another number. By definition, the farther to the RIGHT on a number line, the bigger the number is.
Since A = -.3, we can calculate the values of the other terms and then put them in order from least to greatest...
A^2 = +.09
A^3 = -.027
In this example, A^3 is GREATER than A (since it's closer to 0, and farther to the right on the number line), but since they're both negative, A^2 is greater than them both.
Final Answer: B
GMAT assassins aren't born, they're made,
Rich
For this question, it's important to remember WHY a number is bigger than another number. By definition, the farther to the RIGHT on a number line, the bigger the number is.
Since A = -.3, we can calculate the values of the other terms and then put them in order from least to greatest...
A^2 = +.09
A^3 = -.027
In this example, A^3 is GREATER than A (since it's closer to 0, and farther to the right on the number line), but since they're both negative, A^2 is greater than them both.
Final Answer: B
GMAT assassins aren't born, they're made,
Rich
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We should keep in mind that when a negative number is raised to an even power, the result is positive, and when a negative number is raised to an odd power, the result is negative. Thus, a^2 is the largest among a, a^2, and a^3. Furthermore, we should keep in mind that when we raise a negative proper fraction to the third power, the result is a larger negative number. Thus, since a = -0.3:boomgoesthegmat wrote:If a = -0.3, which of the following is true?
A) a < a^2 < a^3
B) a < a^3 < a^2
C) av2 < a < a^3
D) av2 < a^3 < a
E) a^3 < a < a^2
a < a^3 < a^2, or -0.3 < -0.027 < 0.09
Answer: B
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