The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above?
A) I and II
B) I and III
C) II and III
D) II and IV
E) III and IV
OA: D
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The graph of the equation xy = k,
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boomgoesthegmat
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The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above?
A) I and II
B) I and III
C) II and III
D) II and IV
E) III and IV
OA: D
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OptimusPrep
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- Posts: 410
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- GMAT Score:770
We are given that xy = -ve. This means x and y will have different signs.boomgoesthegmat wrote:
The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above?
A) I and II
B) I and III
C) II and III
D) II and IV
E) III and IV
OA: D
Hence when x > 0, y < 0 {Quadrant IV}
And when x < 0, y > 0 {Quadrant II}
Correct Option: D
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Hi All,
We're told that the graph of the equation (X)(Y) = K, where K < 0. We're asked for the two quadrants in which that graph would lie. This question can be solved by TESTing VALUES.
We're told that K is NEGATIVE. Let's TEST K = -2
(X)(Y) = -2
There are LOTS of different 'pairs' of values for X and Y that would fit this equation (since X and Y aren't necessarily integers). Here are two co-ordinates that are possible:
(X, Y)
(2, -1) --> this is in Quadrant 4
(-2, 1) --> this is in Quadrant 2
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
We're told that the graph of the equation (X)(Y) = K, where K < 0. We're asked for the two quadrants in which that graph would lie. This question can be solved by TESTing VALUES.
We're told that K is NEGATIVE. Let's TEST K = -2
(X)(Y) = -2
There are LOTS of different 'pairs' of values for X and Y that would fit this equation (since X and Y aren't necessarily integers). Here are two co-ordinates that are possible:
(X, Y)
(2, -1) --> this is in Quadrant 4
(-2, 1) --> this is in Quadrant 2
Final Answer: D
GMAT assassins aren't born, they're made,
Rich
