Averages and median
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The key word in this question is MUST. As in, which of the following MUST be true. So, if it's possible that one scenario is not true, we can eliminate it.Last month, 15 homes were sold in Town X. The average sale price of the homes was $150,000 and the median sale price was $130,000. Which of the following statements must be true?
I. at least one of the homes was sold for more than $165,000
II. at least one of the homes was sold for more than $13,000 but less than $150,000
III. at least one of the homes was sold for less than $130,000
A) I only
B) II only
C) III only
D) I and II only
E) I and III only
OA A
So, let's looks at one possible scenario and see which answer choices we can eliminate.
Aside: To make things simpler, let's divide all of the prices by 1000.
First, we'll use a nice rule that says: sum of all values = (mean)(number of values)
So, the sum of all 15 prices = ($150)(15) = $2250.
If the median is $130, then the middlemost value is $130
So, one possible scenario is:
130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 430
Aside: To find the last value (430), I took the sum of all 15 numbers (2250) and subtracted (14)(130)
Notice that this scenario tells us that II and III need not be true (since our scenario does not conform to either one).
Since answer choices B, C, D and E all include either II or III, we can eliminate them.
This leaves us with A, which must be the correct answer.
Cheers,
Brent
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Try to prove that the answer choices DON'T have to be true.Last month 15 homes were sold in town X. The average sale price of the homes were $150,000 & the median sale price was $130,000. Which of the following statements MUST be true?
1) At least one of the homes was sold for more than $165,000
2) At least one of the homes was sold for more than $130,000 & less than $150,000.
3) At least one of the homes was sold for less than $130,000.
(A) I only
(B) II only
(C) III only
(D) I and II
(E) I and III
To make the math easier, divide all of the given numbers by 1000.
The sum of the 15 prices = 15*150 = 2250.
The following solution is similar to Brent's, with one suggestion:
Before testing cases, look for a statement that seems easy to disprove.
If it's possible to have a sum of 2250 without including a price below 130, we can eliminate any answer choice that includes III.
Since the median price is 130, it's possible that 14 of the homes were sold for 130 each.
The price of the 15th home would then be 2250 - 14*130 = 430, yielding the following list of prices:
130, 130....130, median=130, 130...130, 430.
Eliminate any answer choice that includes III, since the list above does not include a price below 130.
Eliminate C and E.
Eliminate any remaining answer choice that includes II, since the list above does not include a price between 130 and 150.
Eliminate B and D.
The correct answer is A.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
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Hi Brent,
Can you please explain a little further.
I am very confused with this question. also what level do you think this question is?
Can you please explain a little further.
I am very confused with this question. also what level do you think this question is?
Brent@GMATPrepNow wrote:The key word in this question is MUST. As in, which of the following MUST be true. So, if it's possible that one scenario is not true, we can eliminate it.Last month, 15 homes were sold in Town X. The average sale price of the homes was $150,000 and the median sale price was $130,000. Which of the following statements must be true?
I. at least one of the homes was sold for more than $165,000
II. at least one of the homes was sold for more than $13,000 but less than $150,000
III. at least one of the homes was sold for less than $130,000
A) I only
B) II only
C) III only
D) I and II only
E) I and III only
OA A
So, let's looks at one possible scenario and see which answer choices we can eliminate.
Aside: To make things simpler, let's divide all of the prices by 1000.
First, we'll use a nice rule that says: sum of all values = (mean)(number of values)
So, the sum of all 15 prices = ($150)(15) = $2250.
If the median is $130, then the middlemost value is $130
So, one possible scenario is:
130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 130, 430
Aside: To find the last value (430), I took the sum of all 15 numbers (2250) and subtracted (14)(130)
Notice that this scenario tells us that II and III need not be true (since our scenario does not conform to either one).
Since answer choices B, C, D and E all include either II or III, we can eliminate them.
This leaves us with A, which must be the correct answer.
Cheers,
Brent
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Can you tell me what part of my solution you'd like explained further?Amrabdelnaby wrote:Hi Brent,
Can you please explain a little further.
I am very confused with this question. also what level do you think this question is?
I'd place this question in the 650 range.
Cheers,
Brent
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I read your answer many times and i came to this conclusion:
Because statement 1 says atleast,i tried to counter it by trying to put the numbers less than 165K
in order to do so i maximized all the numbers prior to the median by making them 130 as well.
So now i have we 8 houses that cost 8(130k) = 1040k
now we have 2250k - 1040k for the remaining 6 houses. aka 1210k for the remaining 6 houses
so now if i distribute the 1210k by the remaining 6 i will get =201K and some change
which means that we can't have any house less than 165K
so statement 1 must be true.
Now since we can't have any house less than 165K and the rest are 130K we won't have any houses sold between 130K and 150K so statement 2 is wrong and also statement 3 is wrong coz no house can be sold for less than 130K.
is this thinking process correct?
please advise
quote="Brent@GMATPrepNow"]
I'd place this question in the 650 range.
Cheers,
Brent[/quote]
Because statement 1 says atleast,i tried to counter it by trying to put the numbers less than 165K
in order to do so i maximized all the numbers prior to the median by making them 130 as well.
So now i have we 8 houses that cost 8(130k) = 1040k
now we have 2250k - 1040k for the remaining 6 houses. aka 1210k for the remaining 6 houses
so now if i distribute the 1210k by the remaining 6 i will get =201K and some change
which means that we can't have any house less than 165K
so statement 1 must be true.
Now since we can't have any house less than 165K and the rest are 130K we won't have any houses sold between 130K and 150K so statement 2 is wrong and also statement 3 is wrong coz no house can be sold for less than 130K.
is this thinking process correct?
please advise
quote="Brent@GMATPrepNow"]
Can you tell me what part of my solution you'd like explained further?Amrabdelnaby wrote:Hi Brent,
Can you please explain a little further.
I am very confused with this question. also what level do you think this question is?
I'd place this question in the 650 range.
Cheers,
Brent[/quote]
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Be careful.Amrabdelnaby wrote: So now i have we 8 houses that cost 8(130k) = 1040k
now we have 2250k - 1040k for the remaining 6 houses. aka 1210k for the remaining 6 houses
so now if i distribute the 1210k by the remaining 6 i will get =201K and some change
which means that we can't have any house less than 165K
The remaining 6 houses must add to 1210K and 1210k/6 =201K + change
However, this does NOT mean that NONE of the remaining 6 houses are less than 165K.
We could have the following 6 prices 160K, 160K, 160K, 160K, 160K, 410K
We CAN says that AT LEAST ONE house will be greater than $165K
Cheers,
Brent