Mixture

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Mixture

by talaangoshtari » Sun Nov 08, 2015 8:20 pm

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by theCEO » Sun Nov 08, 2015 10:10 pm
talaangoshtari wrote:Image
Weight of vinegar / total weight of solution = 4/10
Weight of vinegar / 12 = 4/10
Weight of vinegar = 4.8

To make a 25% vinegar solution: we need to add x oil
4.8 ounce of vinegar / (12 + x)ounces = 25/100
480 = 300 + 25x
180 = 25x -> x = 7.2

Therefore we need to add 7.2ounce of oil

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by GMATGuruNY » Mon Nov 09, 2015 3:09 am
talaangoshtari wrote:Image
Since the 12-ounce vineger-and-oil-mixture is 40% vinegar, the amount of vinegar = (40/100)(12) = 4.8 ounces.

Since the resulting mixture must be 25% vinegar, these 4.8 ounces of vinegar must constitute 25% of the resulting mixture:
(4.8) = (25/100)x
4.8 = (1/4)x
19.2 = x.

Since the total volume increases from 12 ounces to 19.2 ounces, the amount of added oil = (new volume) - (old volume) = 19.2 - 12 = 7.2 ounces.
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by talaangoshtari » Mon Nov 09, 2015 4:28 am
Hi GMATGuruNY,

How can we solve this problem by using alligation method?

I solved it but I couldn't find the answer:

40-----------25-----------0, so, V:O is 5:3.

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by talaangoshtari » Mon Nov 09, 2015 10:01 am
How should I find the last part of this solution?

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by sudh » Mon Nov 09, 2015 5:32 pm
talaangoshtari wrote:Hi GMATGuruNY,

How can we solve this problem by using alligation method?

I solved it but I couldn't find the answer:

40-----------25-----------0, so, V:O is 5:3.
The original 5 parts of "Vinegar & Oil" are the same and we are adding only the 3 parts of "Oil"
5 parts = 12 ounces
3 parts = 3 * 12/5 = 7.2 ounces

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by talaangoshtari » Mon Nov 09, 2015 5:45 pm
Hi sudh,

Isn't the 5 parts the vinegar only?

O/V+O = 3/8?

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by talaangoshtari » Tue Nov 10, 2015 11:40 pm
Thank you everyone for clearing my doubts.