Q14:
$10,000 is deposited in a certain account that pays r percent annual interest compounded
annually, the amount D(t), in dollars, that the deposit will grow to in t years is given by
D(t) = 10,000 {1+(r/100)}t. What amount will the deposit grow to in 3 years?
(1) D(t) = 11,000
(2) r =10
OA is D. My answer would be B.
I found this explanation on web but i was not able to understand it.
"The formula for compounde intrest is D{t,c}= Deposit{1+(r/c)}^tc when t is the Time of deposit r is Rate and c is the number of compounde calculations in each period of time.
By comparing the given formula by general formula and the mentioned 3 years in the question it will be obviouse that each statment alone can answer the question. Because all we need is r and the rest is given."
Thanks,
Deposit Amount
This topic has expert replies
Are you sure the first condition is D(t)=11,000 and not D(1) = 11,000?
It is weird to see D(t) = constant and D(t) = 10,000 {1+(r/100)}t.
If D(1) = 11,000 then r = 10 and D(3) can therefore be determined. Hence the answer 'D'
It is weird to see D(t) = constant and D(t) = 10,000 {1+(r/100)}t.
If D(1) = 11,000 then r = 10 and D(3) can therefore be determined. Hence the answer 'D'
i understand that once we get to know t ..answer becomes D but problem is we do not get t from given statement.
I did copy -paste so pretty sure did not miss anything from orig question.
This is Set 18 Question 14.
I did copy -paste so pretty sure did not miss anything from orig question.
This is Set 18 Question 14.