x, 3, 1, 12, 8
If x is an integer, is the median of the 5 numbers shown greater than the
average (arithmetic mean) of the 5 numbers ?
(1) x > 6
(2) x is greater than the median of the 5 numbers.
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IMO E
X is greter than median, hence x can not be median - which makes 8 as median
X can be any thing greter than 8 (greter than 12 too...)
let's say 9 - which makes mean as 31/5, which is lesser than median
let' say 13 - which makes mean as 7, which is lesser than median
let's say 22 - which makes mean as 46/5, which is greter than median
unconsistent results and hence E
X is greter than median, hence x can not be median - which makes 8 as median
X can be any thing greter than 8 (greter than 12 too...)
let's say 9 - which makes mean as 31/5, which is lesser than median
let' say 13 - which makes mean as 7, which is lesser than median
let's say 22 - which makes mean as 46/5, which is greter than median
unconsistent results and hence E
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