n divisible by 6

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n divisible by 6

by j_shreyans » Wed Sep 10, 2014 11:06 pm
Is the positive integer n divisible by 6?

(1) n^2/180 is an integer.

(2) 144/n^2 is an integer

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by GMATinsight » Thu Sep 11, 2014 4:12 am
j_shreyans wrote:Is the positive integer n divisible by 6?

(1) n^2/180 is an integer.

(2) 144/n^2 is an integer

OAA
Question : Is the positive integer n divisible by 6?
Question : Is n Multiple of 2 as well as 3?

Statement 1) n^2/180 is an integer.
i.e. n^2 = 2^2 x 3^2 x 5 x A where A is any Integer
i.e. n is a multiple of 2 as well as 3
SUFFICIENT

Statement 2) 144/n^2 is an integer
i.e. 2^4 x 3^2 is divisible by n^2

now it is possible for n = 6 (a multiple of 6
also it is possible for n = 4 which is not a multiple of 6
Inconsistent answer therefore
NOT SUFFICIENT

Answer: Option A
Last edited by GMATinsight on Mon Oct 12, 2015 7:44 pm, edited 1 time in total.
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by Brent@GMATPrepNow » Thu Sep 11, 2014 6:35 am
j_shreyans wrote:Is the positive integer n divisible by 6?

(1) n²/180 is an integer.

(2) 144/n² is an integer

OAA
NOTE: This question is VERY similar to this one: https://www.beatthegmat.com/ds-problem-t279217.html

Okay, a lot of integer property questions can be solved using prime factorization.
For questions involving divisibility, divisors, factors and multiples, we can say:
If N is divisible by k, then k is "hiding" within the prime factorization of N

Consider these examples:
24 is divisible by 3 because 24 = (2)(2)(2)(3)
Likewise, 70 is divisible by 5 because 70 = (2)(5)(7)
And 112 is divisible by 8 because 112 = (2)(2)(2)(2)(7)
And 630 is divisible by 15 because 630 = (2)(3)(3)(5)(7)

For more on this concept, see the 2nd half of this free video: https://www.gmatprepnow.com/module/gmat- ... /video/825

------------------------------

Okay, onto the question!

Target question: Is the positive integer n divisible by 6?

Statement 1: n²/180 is an integer
This tells us that n² is DIVISIBLE by 180
This means that 180 is "hiding in the prime factorization of n²
180 = (2)(2)(3)(3)(5)
So, n² = (2)(2)(3)(3)(5)(?)(?)(?)(?)

Aside: the (?)'s represent other possible primes in the prime factorization of n²

Rewrite as (n)(n) = [(2)(3)(5)(?)(?)][(2)(3)(5)(?)(?)]
This tells us that we can be certain that n = (2)(3)(5)(?)(?)
At this point it is clear that n is divisible by 6
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: 144/n² is an integer
There are several values of n that satisfy this condition. Here are two:
Case a: n = 1. Notice that 144/1² = 144, and 144 is an integer. In this case n is NOT divisible by 6
Case b: n = 6. Notice that 144/6² = 4, and 4 is an integer. In this case n IS divisible by 6
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer = A

--------------------

Here are a few more questions that require us to understand the relationship between divisibility and prime factorization:
https://www.beatthegmat.com/factors-t272765.html
https://www.beatthegmat.com/do-t-and-12- ... 74544.html
https://www.beatthegmat.com/is-xy-a-mult ... 74522.html
https://www.beatthegmat.com/confused-nee ... 71655.html
https://www.beatthegmat.com/multiple-of-990-t272719.html
https://www.beatthegmat.com/if-n-t-3-for ... 48420.html

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by prada » Mon Oct 12, 2015 5:12 pm
GMATinsight wrote:
j_shreyans wrote:


Statement 2) 144/n^2 is an integer
i.e. 2^4 x 3^3 is divisible by n^2


Answer: Option A
Sorry for bumping an old thread (linked from GMATPREP) but shouldn't it be 2^4 x 3^2?
I think you did the PF of 144?

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by GMATinsight » Mon Oct 12, 2015 7:46 pm
prada wrote:
GMATinsight wrote:
j_shreyans wrote:


Statement 2) 144/n^2 is an integer
i.e. 2^4 x 3^3 is divisible by n^2


Answer: Option A
Sorry for bumping an old thread (linked from GMATPREP) but shouldn't it be 2^4 x 3^2?
I think you did the PF of 144?
Yes, It was PF of 144. I made a typo mistake. Thanks for taking note of it. Have made the necessary changes.
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