Guys ,
in the attachment you can find the question pls help me out.
Thanks
Shreyans
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Please post the question in forum and not in the doc and I will be happy to answer.
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∆ACD:
Since each side has a length of 3, ∆ACD is equilateral.
Area of an equilateral triangle = (s²/4)√3.
Thus, the area of ∆ACD = (3²/4)√3 = (9/4)√3.
∆ABE:
∆ABE is a 30-60-90 triangle.
In a 30-60-90 triangle, the sides are in the following ratio:
1 - √3 - 2.
Since AB=1, BE=√3, as shown in the figure above.
Thus, the area of ∆ABE = (1/2)bh = (1/2)(AB)(BE) = (1/2)(1)(√3) = (√3)/2.
BCDE:
∆ACD - ∆ABE = (9/4)√3 - (√3)/2 = (9/4)√3 - (2/4)√3 = (7/4)√3.
The correct answer is B.
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Hi j_shreyans,
The GMAT tests a variety of concepts regarding right triangles. One of those concepts involves the rules behind a 30/60/90 triangle.
In a 30/60/90, the ratio of the side lengths is 1:√3:2
This means that the side across from the 90 degree angle is 2 times the length of the side across from the 30 degree angle. The side across from the 60 degree angles is √3 times the length of the side across from the 30 degree angle.
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The GMAT tests a variety of concepts regarding right triangles. One of those concepts involves the rules behind a 30/60/90 triangle.
In a 30/60/90, the ratio of the side lengths is 1:√3:2
This means that the side across from the 90 degree angle is 2 times the length of the side across from the 30 degree angle. The side across from the 60 degree angles is √3 times the length of the side across from the 30 degree angle.
GMAT assassins aren't born, they're made,
Rich
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GMATinsight
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Hi j_Shreyanj_shreyans wrote:Hi ,
Can you pls advise about the ratio.
1 - √3 - 2.
Thanks ,
Shreyans
Please check the following link to understand more about 30-60-90 Triangle
https://www.regentsprep.org/Regents/math ... Ltri30.htm
Please note that this is a MUST KNOW Concept for GMAT Geometry Questions
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