pl help solve

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pl help solve

by Nijo » Fri Aug 15, 2014 5:37 am
Of the students who eat in the cafeteria, each likes or dislikes lima beans and each likes or dislikes brussel sprouts. Of these 2/3 rd dislike lima beans and of those who dislike beans, 3/5th dislike sprouts. How many like sprouts but dislike beans?
1) There are 120 students in all
2) 40 students like beans

OA is D

Many thanks, also if someone could tell me where can I find more questions like these, I need more practise

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by Brent@GMATPrepNow » Fri Aug 15, 2014 5:43 am
Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans and each student either like or dislikes Brussels sprouts. Of theses students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike Brussels sprouts. How many of the students like Brussels sprouts but dislike lima beans?

(1) 120 students eat in the cafeteria
(2) 40 of the students like lima beans.
We can use the Double Matrix Method to solve this question. This technique can be used for most questions featuring a population in which each member has two characteristics associated with it.
Here, we have a population of students, and the two characteristics are:
- like Brussels sprouts or dislike Brussels sprouts
- like lima beans or dislike lima beans

So, we can set up our diagram as follows:
Image

Target question: How many of the students like Brussels sprouts but dislike lima beans?
Let's place a STAR in the box representing those students who like Brussels sprouts but dislike lima beans.
Image

Since we don't know the TOTAL NUMBER of students, let's let x represent the total student population. So, we'll add that to our diagram as well.
Image

Given: 2/3 dislike lima beans
So, (2/3)x = total number of students who dislike lima beans
This means the other 1/3 LIKE lima beans. In other words, (1/3)x = total number of students who LIKE lima beans.
We'll add that to the diagram:
Image

Given: Of those who dislike lima beans, 3/5 also dislike Brussels sprouts
If (2/3)x = total number of students who dislike lima beans, then (3/5)(2/3)x = total number of students who dislike lima beans AND dislike Brussels sprouts.
(3/5)(2/3)x simplifies to (2/5)x, so we'll add that to our diagram:
Image

Finally, since the two boxes in the right-hand column must add to (2/3)x, we know that the top-right box must = (4/15)x [since (2/3)x - (2/5)x = (4/15)x]
So, we can add that to the diagram:
Image

Great! We're now ready to examine the statements.

Statement 1: 120 students eat in the cafeteria
In other words, x = 120
Plug x = 120 into the top-right box to get: (4/15)(120) = 32
So, there are 32 students who like Brussels sprouts but dislike lima beans.
Image
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: 40 of the students like lima beans.
The left-hand column represents students who like lima beans.
In total, (1/3)x = total number of students who LIKE lima beans.
So, statement 2 is telling us that (1/3)x = 40
We can solve the equation to conclude that x = 120
Once we know the value of x, we can determine the number of students who like Brussels sprouts but dislike lima beans (we already did so in statement 1)
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = D

-------------------------------------

NOTE: This question type is VERY COMMON on the GMAT, so be sure to master the technique.

To learn more about the Double Matrix Method, watch our free video: https://www.gmatprepnow.com/module/gmat- ... ems?id=919

Once you're familiar with this technique, you can attempt these additional practice questions:

Easy Problem Solving questions
- https://www.beatthegmat.com/the-aam-aadm ... 72242.html
- https://www.beatthegmat.com/finance-majo ... 67425.html

Medium Problem Solving questions
- https://www.beatthegmat.com/probability- ... 73360.html
- https://www.beatthegmat.com/posted-speed ... 72374.html
- https://www.beatthegmat.com/motel-t271938.html
- https://www.beatthegmat.com/of-the-appli ... 70255.html
- https://www.beatthegmat.com/opening-nigh ... 64869.html
- https://www.beatthegmat.com/ds-french-ja ... 22297.html

Difficult Problem Solving questions
- https://www.beatthegmat.com/ratio-problem-t268339.html
- https://www.beatthegmat.com/overlapping- ... 65223.html
- https://www.beatthegmat.com/fractions-t264254.html
- https://www.beatthegmat.com/overlapping- ... 64092.html
- https://www.beatthegmat.com/mba/2011/05/ ... question-2

Easy Data Sufficiency questions
- https://www.beatthegmat.com/for-what-per ... 70596.html
- https://www.beatthegmat.com/ds-quest-t187706.html

Medium Data Sufficiency questions
- https://www.beatthegmat.com/sets-matrix-ds-t271914.html
- https://www.beatthegmat.com/each-of-peop ... 71375.html
- https://www.beatthegmat.com/a-manufacturer-t270331.html
- https://www.beatthegmat.com/in-costume-f ... 69355.html
- https://www.beatthegmat.com/mba/2011/05/ ... question-1

Difficult Data Sufficiency questions
- https://www.beatthegmat.com/double-set-m ... 71423.html
- https://www.beatthegmat.com/sets-t269449.html
- https://www.beatthegmat.com/mba/2011/05/ ... question-3

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by GMATGuruNY » Fri Aug 15, 2014 6:02 am
Of the students who eat in the cafeteria, each likes or dislikes lima beans and each likes or dislikes brussel sprouts. Of these 2/3 rd dislike lima beans and of those who dislike beans, 3/5th dislike sprouts. How many like sprouts but dislike beans?
1) There are 120 students in all
2) 40 students like beans
Of the students who eat in a certain cafeteria, each student either likes or dislikes lima beans, and each student either likes or dislikes brussel sprouts. Of these students, 2/3 dislike lima beans; and of those who dislike lima beans, 3/5 also dislike brussel sprouts. How many of the students like brussels sprouts but dislike lima beans?

(1) 120 students eat in the cafeteria
(2) 40 students like lima beans.
The solution below is similar to Brent's.
The key difference is that the unknowns in the grid are represented as integers values rather than fractions.

This is an EITHER/OR group question.
Every student EITHER dislikes lima beans OR likes lima beans.
Every student EITHER dislikes brussels sprouts OR likes brussels sprouts.
For an EITHER/OR group problem, use a GROUP GRID to organize the data.

Let DL = dislikes limas, LL = likes limas, DB = dislikes brussels sprouts, and LB = likes brussels sprouts.
There are two fractions in the question stem: 2/3 and 3/5.
Since the product of the denominators = 3*5 = 15, let the TOTAL = 15x.
Here's the grid:
_______________DL______LL_______Total

DB:

LB:

Total:___________________________15x
Now let's use the information in the question stem to complete as much of the grid as possible.
Values in the grid have to add up horizontally and vertically.
As soon as we know 2 entries in a row or a column, we can calculate the remaining entry in that row or column.

2/3 dislike lima beans:
Since (2/3)(15x) = 10x, we get:
_______________DL______LL_______Total

DB:

LB:

Total:__________10x______5x_______15x
Of those who dislike lima beans, 3/5 also dislike brussel sprouts.
Since (3/5)(10x) = 6x, we get:
_______________DL______LL_______Total

DB:____________6x_______________

LB:____________4x_________________

Total:_________10x______5x_______15x
The question stem asks for the number of students who like brussels sprouts but dislike lima beans: 4x.
To determine the value of 4x, we need to know the value of x.
Question rephrased: What is the value of x?

Statement 1: 120 students eat in the cafeteria
Since the total number of students = 15x, we get:
15x = 120
x = 8.
SUFFICIENT.

Statement 2: 40 students like lima beans.
Since the total number of students who like lima beans = 5x, we get:
5x = 40
x = 8.
SUFFICIENT.

The correct answer is D.
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