If 135 is a factor of 2^a.3^b.5^c, where a, b, and c are non negative integers, which of the following CANNOT be the value of abc?
A. 8
B. 6
C. 4
D. 2
E. 0
Made Up!
135 is a factor of 2^a.3^b.5^c
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Last edited by sanju09 on Sat Aug 02, 2014 10:16 pm, edited 2 times in total.
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135 = 5 x 3 x 3 x 3
2^a * 3^b * 5^c * _
Minimum value of
a = 0
b = 3
c = 1
To find: a*b*c
{A} 3 = 1 x 3 x 1 YES
{B} 6 = 1 x 3 x 2 YES
{C} 8 = 2 x 2 x 2 "we need at least 3 3's"
{D} 9 = 1 x 3 x 3 YES
{E} 12 = 2 x 3 x 2 YES
[spoiler]{C}[/spoiler]
2^a * 3^b * 5^c * _
Minimum value of
a = 0
b = 3
c = 1
To find: a*b*c
{A} 3 = 1 x 3 x 1 YES
{B} 6 = 1 x 3 x 2 YES
{C} 8 = 2 x 2 x 2 "we need at least 3 3's"
{D} 9 = 1 x 3 x 3 YES
{E} 12 = 2 x 3 x 2 YES
[spoiler]{C}[/spoiler]
R A H U L
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135 is a factor of 2^a.3^b.5^csanju09 wrote:If 135 is a factor of 2^a.3^b.5^c, where a, b, and c are positive integers, which of the following CANNOT be the value of abc?
A. 3
B. 6
C. 8
D. 9
E. 12
Made Up!
135 = 3x3x3x5 = 3^3 x 5^1
therefore, 3^3 x 5^1 is a factor of 2^a.3^b.5^c
i.e. Comparing both sides
b must be 3 or a greater Integer and c must be 1 or a greater integer
therefore, abc must be greater than 3*1
Let's Check the options
A) 3
if a = 1, b = 3 and c = 1
2^a.3^b.5^c = 2 x 3^3 x 5^1 = 270 and 135 is factor if 270
So WRONG OPTION
B) 6
if a = 2, b = 3 and c = 1
2^a.3^b.5^c = 2^2 x 3^3 x 5^1 = 540 and 135 is factor if 540
So WRONG OPTION
C) 8
if a = 2, b = 4 and c = 1
2^a.3^b.5^c = 2^2 x 3^4 x 5^1 = 1620 and 135 is factor if 1620
So WRONG OPTION
D) 9
if a = 3, b = 3 and c = 1
2^a.3^b.5^c = 2^3 x 3^3 x 5^1 = 1080 and 135 is factor if 1080
So WRONG OPTION
E) 12
if a = 4, b = 3 and c = 1
2^a.3^b.5^c = 2^4 x 3^3 x 5^1 = 2160 and 135 is factor if 2160
So WRONG OPTION
All Options seem Wrong.... Ouch!!!
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(F):: none of the above.
For 135 to be a factor of 2ᵃ * 3ᵇ * 5ᶜ, we need b ≥ 3 and c ≥ 1. So ANY integer ≥ 3 will suffice: simply make c = 1 and b = the integer itself.
For 135 to be a factor of 2ᵃ * 3ᵇ * 5ᶜ, we need b ≥ 3 and c ≥ 1. So ANY integer ≥ 3 will suffice: simply make c = 1 and b = the integer itself.
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Hi sanju09,
This is a poorly designed question. I understand what you were "going for" (prime factorization rules and how you can use them to figure out possibilities), but the question isn't properly designed. Here's why:
The prime factors of 135 are 3x3x3x5.
We're told that A, B and C are positive integers. Since 135 is a factor of (2^A)(3^B)(5^C), we know that....
A can be ANY positive integer
B can be any positive integer greater than or equal to 3
C can be ANY positive integer
If we choose, A=1, C=1, then B can be ANY integer greater than or equal to 3....
Thus, ABC can equal 3, 4, 5, 6, 7, 8 etc. So all of the answers are possible.
GMAT assassins aren't born, they're made,
Rich
This is a poorly designed question. I understand what you were "going for" (prime factorization rules and how you can use them to figure out possibilities), but the question isn't properly designed. Here's why:
The prime factors of 135 are 3x3x3x5.
We're told that A, B and C are positive integers. Since 135 is a factor of (2^A)(3^B)(5^C), we know that....
A can be ANY positive integer
B can be any positive integer greater than or equal to 3
C can be ANY positive integer
If we choose, A=1, C=1, then B can be ANY integer greater than or equal to 3....
Thus, ABC can equal 3, 4, 5, 6, 7, 8 etc. So all of the answers are possible.
GMAT assassins aren't born, they're made,
Rich
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Rich, there's no need to pile on Sanju here. I made the exact same point in my post - give the guy a break!
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OOPS...
Bad selection of answer choices. Edited. Thanks for the feed backs.
Bad selection of answer choices. Edited. Thanks for the feed backs.
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
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Nice prescription MattMatt@VeritasPrep wrote:Rich, there's no need to pile on Sanju here. I made the exact same point in my post - give the guy a break!
Question needs corrections at two places, one in wordings, "a, b, and c are non negative integers", and the other, of course in the answer choices. Thanks for waking me up.
Please re-read it as below:
If 135 is a factor of 2^a.3^b.5^c, where a, b, and c are non negative integers, which of the following CANNOT be the value of abc?
A. 8
B. 6
C. 4
D. 2
E. 0
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
- sanju09
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Very genuine Ouch!!! Sir, thanks and congratulations for spotting it before others.GMATinsight wrote:135 is a factor of 2^a.3^b.5^csanju09 wrote:If 135 is a factor of 2^a.3^b.5^c, where a, b, and c are positive integers, which of the following CANNOT be the value of abc?
A. 3
B. 6
C. 8
D. 9
E. 12
Made Up!
135 = 3x3x3x5 = 3^3 x 5^1
therefore, 3^3 x 5^1 is a factor of 2^a.3^b.5^c
i.e. Comparing both sides
b must be 3 or a greater Integer and c must be 1 or a greater integer
therefore, abc must be greater than 3*1
Let's Check the options
A) 3
if a = 1, b = 3 and c = 1
2^a.3^b.5^c = 2 x 3^3 x 5^1 = 270 and 135 is factor if 270
So WRONG OPTION
B) 6
if a = 2, b = 3 and c = 1
2^a.3^b.5^c = 2^2 x 3^3 x 5^1 = 540 and 135 is factor if 540
So WRONG OPTION
C) 8
if a = 2, b = 4 and c = 1
2^a.3^b.5^c = 2^2 x 3^4 x 5^1 = 1620 and 135 is factor if 1620
So WRONG OPTION
D) 9
if a = 3, b = 3 and c = 1
2^a.3^b.5^c = 2^3 x 3^3 x 5^1 = 1080 and 135 is factor if 1080
So WRONG OPTION
E) 12
if a = 4, b = 3 and c = 1
2^a.3^b.5^c = 2^4 x 3^3 x 5^1 = 2160 and 135 is factor if 2160
So WRONG OPTION
All Options seem Wrong.... Ouch!!!
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com