Hello,
Can you please tell my if my solution is correct here:
Pedro has some coins in his pocket, some are 5-cent coins and some are 25-cent coins. If the average value of each coin in Pedro's pocket is 10 cents and he has $8 in his pocket, what is the total value of his 5-cent coins?
A) $1
B) $2
C) $3
D) $4
E) $6
OA Given: E
This is from "GMAT Word Problems" book.
f --------------f+tf-------------------tf
5---------------10---------------------25
f/tf = (25-10)/(10-5) = 3/1
Since the total is $8
3x + x = 800
=> 4x = 800
=> x = 200
Tot. value of five cent coins = 3x = 3(200) = 600 cents = $6/-
I was wondering if this is correct?
Thanks a lot,
Sri
Total value of 5-cent coins
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Hi Sri,
You correctly solved the ratio of coins(5-cent coins to 25-cent coins is 3:1)
However, you made a mistake in your later calculations. The VALUES of the coins have to be accounted for.
So your equation should be....
3X(.05) + X(.25) = 8.00
Multiplying by 100 will remove the decimals:
3X(5) + X(25) = 800
NOW you can solve for X...
15X + 25X = 800
40X = 800
X=20
Thus, there are 60 5-cent pieces and 20 25-cent pieces.
GMAT assassins aren't born, they're made,
Rich
You correctly solved the ratio of coins(5-cent coins to 25-cent coins is 3:1)
However, you made a mistake in your later calculations. The VALUES of the coins have to be accounted for.
So your equation should be....
3X(.05) + X(.25) = 8.00
Multiplying by 100 will remove the decimals:
3X(5) + X(25) = 800
NOW you can solve for X...
15X + 25X = 800
40X = 800
X=20
Thus, there are 60 5-cent pieces and 20 25-cent pieces.
GMAT assassins aren't born, they're made,
Rich
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This is a MIXTURE problem.gmattesttaker2 wrote:Hello,
Can you please tell my if my solution is correct here:
Pedro has some coins in his pocket, some are 5-cent coins and some are 25-cent coins. If the average value of each coin in Pedro's pocket is 10 cents and he has $8 in his pocket, what is the total value of his 5-cent coins?
A) $1
B) $2
C) $3
D) $4
E) $6
A certain number of 5-cent coins are combined with a certain number of 25-cent coins to form a MIXTURE with an average value of 10 cents per coin.
To solve, we can use ALLIGATION -- a very efficient way to handle MIXTURE PROBLEMS.
Step 1: Plot the 3 coin values on a number line, with the values for the two types of coins on the ends and the value for the mixture in the middle.
5-----------10-----------25
Step 2: Calculate the distances between the values.
5-----5-----10-----15-----25
Step 3: Determine the ratio in the mixture.
The required ratio of 5-cent coins to 25-cent coins is equal to the RECIPROCAL of the distances in red.
(5-cent coins) : (25-cent coins) = 15:5 = 3:1.
Implication:
Of every 4 coins, 3 are 5-cent coins and 1 is a 25-cent coin.
Thus:
Total value of every 4 coins = (3*5) + (1*25) = 40 cents.
Since (total value of 3 5-cent coins)/(total value of every 4 coins) = 15/40 = 3/8, the 5-cent coins must account for 3/8 of Pedro's $8:
(3/8) * 8 = 3.
The correct answer is C.
For two similar problems, check here:
https://www.beatthegmat.com/ratios-fract ... 15365.html
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
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