EXPERTS PLEASE HELP
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- [email protected]
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- theCodeToGMAT
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To find:
(x-y)/(x+y) > 1
Statement 1:
x > 0
We have no info about the value of "y"
INSUFFICIENT
Statement 2:
y < 0
we have no info about value of "x"
INSUFFICIENT
Combining
x > 0
y < 0
Still we dont have any idea about the values; we need to have relation between x & y
[spoiler]{E}[/spoiler]
(x-y)/(x+y) > 1
Statement 1:
x > 0
We have no info about the value of "y"
INSUFFICIENT
Statement 2:
y < 0
we have no info about value of "x"
INSUFFICIENT
Combining
x > 0
y < 0
Still we dont have any idea about the values; we need to have relation between x & y
[spoiler]{E}[/spoiler]
R A H U L
GMAT/MBA Expert
- Brent@GMATPrepNow
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NOTE: If we have a feeling that the statements might not be sufficient, we can start TESTING VALUES.If x ≠-y, is (x - y)/(x + y) > 0?
1) x > 0
2) y < 0
Target question: Is (x - y)/(x + y) > 0?
Statement 1: x > 0
There are several values of x and y that satisfy this condition. Here are two:
Case a: x = 2 and y = -1, in which case (x - y)/(x + y) is GREATER THAN 0
Case b: x = 2 and y = -3, in which case (x - y)/(x + y) is LESS THAN 0
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT
Statement 2: y < 0
There are several values of x and y that satisfy this condition. Here are two:
Case a: x = 2 and y = -1, in which case (x - y)/(x + y) is GREATER THAN 0
Case b: x = 2 and y = -3, in which case (x - y)/(x + y) is LESS THAN 0
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT
Statements 1 and 2 combined
There are several values of x and y that satisfy BOTH conditions. Here are two:
Case a: x = 2 and y = -1, in which case (x - y)/(x + y) is GREATER THAN 0
Case b: x = 2 and y = -3, in which case (x - y)/(x + y) is LESS THAN 0
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT
Answer = E
Cheers,
Brent
- sanju09
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(1) If x > 0 then may be (x - y)/(x + y) > 1 only if y < 0, which we don't know. Insufficient[email protected] wrote:
(2) If y < 0, let's plug in x = 2 and y = -3, this would make (x - y)/(x + y) < 0. Again, let's plug in x = -2 and y = -3, this would maintain (x - y)/(x + y) < 0. Then, let's plug in x = 4 and y = -3, this would make (x - y)/(x + y) > 1. Insufficient
When taken together, we have already seen while testing statement (2) that two different positive values of x have given us two different answers, a NO at x = 2, and a YES at x = 4, hence [spoiler]still insufficient.
Take E[/spoiler]
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
- [email protected]
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Hi all,
Thanx for your replies.
Could one please tell me how to solve this Q without plugging values.In sum, I am asking the formal procedure.
Regards,
Mukherjee
Thanx for your replies.
Could one please tell me how to solve this Q without plugging values.In sum, I am asking the formal procedure.
Regards,
Mukherjee
- sanju09
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Hi Tanuj,[email protected] wrote:Hi all,
Thanx for your replies.
Could one please tell me how to solve this Q without plugging values.In sum, I am asking the formal procedure.
Regards,
Mukherjee
When there are possibilities of contradicting answers, which generally happens in YES/NO DS, we either need to be extremely hypothetical or should just rely on approved and easy numbers. Hypothetically, we can believe that no statement alone is sufficient. Hence, with x > 0 and y < 0, we can be sure that x - y is positive and greater than x + y. Now, (x - y)/(x + y) > 1 will be possible only if x + y > 0, but the question as a sum total doesn't pledge that, hence [spoiler](E)[/spoiler] is the right choice.
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com