ZY<XY<0 is |X-Z| + |x| = |Z|
(1) Z<X
(2) Y<0
The answer is D, could you pls explain with testing values?
Absolute Value
This topic has expert replies
-
- Master | Next Rank: 500 Posts
- Posts: 429
- Joined: Wed Sep 19, 2012 11:38 pm
- Thanked: 6 times
- Followed by:4 members
- theCodeToGMAT
- Legendary Member
- Posts: 1556
- Joined: Tue Aug 14, 2012 11:18 pm
- Thanked: 448 times
- Followed by:34 members
- GMAT Score:650
To find: |X-Z| + |x| = |Z|
Statement 1:
Z<X ==> y is +ve ==> x & z both are negative
Both x & z are negative
Let x = -5 & z = -8
=> |-5 + 8 | + |5| = |8|
=> 3 + 5 = 8
=> 8 = 8
SUFFICIENT
Statement 2:
y < 0 ==> x & z are positive & z > x
Let z = 8 & x = 5
=> | 5 - 8 | + |5| = |8|
=> 3 + 5 = 8
= 8 = 8
SUFFICIENT
Answer[spoiler] {D}[/spoiler]
Statement 1:
Z<X ==> y is +ve ==> x & z both are negative
Both x & z are negative
Let x = -5 & z = -8
=> |-5 + 8 | + |5| = |8|
=> 3 + 5 = 8
=> 8 = 8
SUFFICIENT
Statement 2:
y < 0 ==> x & z are positive & z > x
Let z = 8 & x = 5
=> | 5 - 8 | + |5| = |8|
=> 3 + 5 = 8
= 8 = 8
SUFFICIENT
Answer[spoiler] {D}[/spoiler]
R A H U L
- sanju09
- GMAT Instructor
- Posts: 3650
- Joined: Wed Jan 21, 2009 4:27 am
- Location: India
- Thanked: 267 times
- Followed by:80 members
- GMAT Score:760
If ZY < XY < 0, then either Y < 0 and Z, X > 0 or Y > 0 and Z, X < 0.[email protected] wrote:ZY<XY<0 is |X-Z| + |x| = |Z|
(1) Z<X
(2) Y<0
The answer is D, could you pls explain with testing values?
If Y < 0 and Z, X > 0, the condition ZY < XY < 0 will be true only if Z > X.
And if Y > 0 and Z, X < 0, the condition ZY < XY < 0 will be true only if Z < X.
(1) If Z < X, then the condition ZY < XY < 0 is true only if Z, X > 0 and Y < 0. Let's take X = 3 and Z = 2, so that |3 - 2| + |3| is NO ≠|2|. Sufficient
(2) If Y < 0, then the condition ZY < XY < 0 is true only if Z, X > 0 and Z < X. Let's recycle X = 3 and Z = 2, so that |3 - 2| + |3| is NO ≠|2|. [spoiler]Sufficient
Take D
In other words, each statement implies the other, hence D in case of sufficiency otherwise E in case of insufficiency.
[/spoiler]
The mind is everything. What you think you become. -Lord Buddha
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
Sanjeev K Saxena
Quantitative Instructor
The Princeton Review - Manya Abroad
Lucknow-226001
www.manyagroup.com
-
- Master | Next Rank: 500 Posts
- Posts: 429
- Joined: Wed Sep 19, 2012 11:38 pm
- Thanked: 6 times
- Followed by:4 members
Now my question is will we have a scenario where the two sttmnts contradict each other?
Statement one gives us y is positive whereas statement two says its negative!
Thnks
Statement one gives us y is positive whereas statement two says its negative!
Thnks
theCodeToGMAT wrote:To find: |X-Z| + |x| = |Z|
Statement 1:
Z<X ==> y is +ve ==> x & z both are negative
Both x & z are negative
Let x = -5 & z = -8
=> |-5 + 8 | + |5| = |8|
=> 3 + 5 = 8
=> 8 = 8
SUFFICIENT
Statement 2:
y < 0 ==> x & z are positive & z > x
Let z = 8 & x = 5
=> | 5 - 8 | + |5| = |8|
=> 3 + 5 = 8
= 8 = 8
SUFFICIENT
Answer[spoiler] {D}[/spoiler]
- theCodeToGMAT
- Legendary Member
- Posts: 1556
- Joined: Tue Aug 14, 2012 11:18 pm
- Thanked: 448 times
- Followed by:34 members
- GMAT Score:650
No, I don't think so..[email protected] wrote:Now my question is will we have a scenario where the two sttmnts contradict each other?
Statement one gives us y is positive whereas statement two says its negative!
Thnks
Both statement will not contradict because
|X-Z| + |x| = |Z|
Here,
|X-Z| ==> is always the difference between x & z... and signs of x & z will always be same as ZY<XY<0
And, the magnitude of x & z will vary correspondingly based on signs
R A H U L
- GMATGuruNY
- GMAT Instructor
- Posts: 15539
- Joined: Tue May 25, 2010 12:04 pm
- Location: New York, NY
- Thanked: 13060 times
- Followed by:1906 members
- GMAT Score:790
|x-z| = the distance between x and z.
|x| = the distance between x and 0.
|z| = the distance between z and 0.
Constraint in the question stem: zy < xy < 0.
Case 1: If y is POSITIVE, then x and z are NEGATIVE, with z "more negative" than x, so that zy < xy.
Case 2: If y is NEGATIVE, then x and z are POSITIVE, with z "more positive" than x, so that zy < xy.
Case 1:
z<---|x-z|--->x<---|x|--->0..........y
In the number line above, the red portion represents |z|: the distance between z and 0.
|x-z| + |x| is equal to the red portion.
Thus:
|x-z| + |x| = |z|.
Case 2:
y..........0<---|x|--->x<---|x-z|--->z
In the number line above, the red portion represents |z|: the distance between z and 0.
|x-z| + |x| is equal to the red portion.
Thus:
|x-z| + |x| = |z|.
The two statements are IRRELEVANT.
Given that zy < xy < 0, it will ALWAYS be true that |x-z| + |x| = |z|.
Thus:
in statement 1, the answer to the question stem is YES, since it will always be true that |x-z| + |x| = |z|.
In statement 2, the answer to the question stem is YES, since it will always be true that |x-z| + |x| = |z|.
The correct answer is D.
Since the two statements are irrelevant, this problem is flawed.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3