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Area of triangle

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Area of triangle

by sushbis » Tue Oct 04, 2011 11:25 pm
A right triangle is drawn, the opposite site of right angle is 10, sum of the sides next to right angle is 12.
What is the area of the triangle?
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by sl750 » Tue Oct 04, 2011 11:29 pm
a+b=12

a^2+b^2 = 100 (Pythagorean theorem)

a^2+b^2 = (a+b)^2 -2ab

144 -2ab = 100 or ab 22; Area of triangle = 1/2ab or 11
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by Anurag@Gurome » Tue Oct 04, 2011 11:48 pm
sushbis wrote:A right triangle is drawn, the opposite site of right angle is 10, sum of the sides next to right angle is 12.
What is the area of the triangle?
Image

Area of triangle = (1/2) * x * y = xy/2, where x = base, y = height
By Pythagoras Theorem, x² + y² = 10²
x² + y² = (x + y)² - 2xy
10² = 12² - 2xy
2xy = 44 or xy = 22
So, area of triangle = 22/2 = 11 sq units
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by Waqas_Jameel » Fri Sep 13, 2013 1:59 am
Aahhh !! thanks for the answers here ! the answer sheet with me says area is 22 sq units !
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