A circle with diameter 10 is centered on the origin. Which of the following points are on the circle?
a) 5,0
b) 5,5
c) -3, 4
d) 1, -2(sqroot6)
e) -2, 2(sqroot6)
OA is a,c,d
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ganeshrkamath
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Diameter = 10sana.noor wrote:A circle with diameter 10 is centered on the origin. Which of the following points are on the circle?
a) 5,0
b) 5,5
c) -3, 4
d) 1, -2(sqroot6)
e) -2, 2(sqroot6)
OA is a,c,d
Radius = 5
All the points which have distance from the origin = 5 lie on the circle.
In this case, a,c, and d
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Kelley School of Business (Class of 2016)
GMAT Score: 750 V40 Q51 AWA 5 IR 8
https://www.beatthegmat.com/first-attemp ... tml#688494
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vipulgoyal
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the essence is that the digonal must be 5 in order to be it on circle if the any of the two vertices is not zero
for d = {{-2(6)^1/2}^2} + (1)]^2 = (25)^1/2 = 5
a nd c are clearly on circle
for d = {{-2(6)^1/2}^2} + (1)]^2 = (25)^1/2 = 5
a nd c are clearly on circle
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sana.noor
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i understand the question but need reasoning behind the answer choices so starters can understand this issue
b) 5,5 cannot be the point on the circle because when x = 5 y will be zero and as we start decreasing the value of x the value of y increases. when y = 5 then x= 0. thus no such point can exist on the circle.
e) 2(sqroot6) is nearly equals to 5 (4.89). if we draw the diagram we can understand that when x=-2 the value of y will lie outside the circle.
b) 5,5 cannot be the point on the circle because when x = 5 y will be zero and as we start decreasing the value of x the value of y increases. when y = 5 then x= 0. thus no such point can exist on the circle.
e) 2(sqroot6) is nearly equals to 5 (4.89). if we draw the diagram we can understand that when x=-2 the value of y will lie outside the circle.
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Hi sana.noor,
To help you solve this problem, try drawing a circle as the question describes it (on a graph, around the origin, with a diameter of 10, so the radius is 5).
Since the radius is 5, and you're looking for points that are on the circumference of the circle, you can use the Pythagorean Theorem to figure out which points are on the circumference and which ones are not.
For example, with Answer C (-3,4):
1) Graph that point and then draw a line from the origin (0,0) to (-3,4).
2) Notice that it's a diagonal line? You should be able to draw a RIGHT TRIANGLE, using that diagonal line as the hypotenuse.
3) Now, using the values of THAT point, see if Pythagorean Thm balances: A^2 + B^2 = C^2
4) Does (-3)^2 + (4)^2 = 5^2????
5) It DOES!!! So, THAT point is on the circumference.
6) Now try the other points.
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To help you solve this problem, try drawing a circle as the question describes it (on a graph, around the origin, with a diameter of 10, so the radius is 5).
Since the radius is 5, and you're looking for points that are on the circumference of the circle, you can use the Pythagorean Theorem to figure out which points are on the circumference and which ones are not.
For example, with Answer C (-3,4):
1) Graph that point and then draw a line from the origin (0,0) to (-3,4).
2) Notice that it's a diagonal line? You should be able to draw a RIGHT TRIANGLE, using that diagonal line as the hypotenuse.
3) Now, using the values of THAT point, see if Pythagorean Thm balances: A^2 + B^2 = C^2
4) Does (-3)^2 + (4)^2 = 5^2????
5) It DOES!!! So, THAT point is on the circumference.
6) Now try the other points.
GMAT assassins aren't born, they're made,
Rich
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lunarpower
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A multiple-choice problem with 3 correct answers? Huh? Where'd you get this?
Hopefully not from a GMAT source...
Hopefully not from a GMAT source...
Ron has been teaching various standardized tests for 20 years.
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