cube root of x

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cube root of x

by hemant_rajput » Sat May 18, 2013 10:30 am
64. If x is an integer between 2 and 100 and if root x is also an integer,
what is the value of x?
(1) cube root x or (x)^(1/3) is an integer.
(2) 2(cube root x) = root x
Last edited by hemant_rajput on Wed Jul 24, 2013 7:03 am, edited 1 time in total.
I'm no expert, just trying to work on my skills. If I've made any mistakes please bear with me.

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by Atekihcan » Sat May 18, 2013 10:57 am
Possible values of x are 4, 9, 16, 25, 36, 49, 64, and 81

Statement 1: Only possible value of x is 64.
So, statement 1 is sufficient.

Statement 2: I guess this statement originally meant to say 2*(cube root of x) = square root of x
Now, as square root of x is an integer, i.e. left hand side of the equation is an integer, the right-hand side must be an integer too.
So, cube root of x is an integer.
So, statement 2 is same as statement 1.
So, statement 2 is sufficient.

Answer : D

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by Imsukhi » Wed Jul 24, 2013 12:36 am
IMO A

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by Brent@GMATPrepNow » Wed Jul 24, 2013 7:00 am
hemant_rajput wrote:64. If x is an integer between 2 and 100 and if root x is also an integer,
what is the value of x?
(1) cube root x or (x)^(1/3) is an integer.
(2) 2(root 33 x) = root x
Hi hemant_rajput,

Can you tell us what statement 2 is supposed to say? It's not clear what you mean by 2(root 33 x) = root x

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by hemant_rajput » Wed Jul 24, 2013 7:04 am
I'm sorry for creating confusion. I've edited my original post.
I'm no expert, just trying to work on my skills. If I've made any mistakes please bear with me.

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by Brent@GMATPrepNow » Wed Jul 24, 2013 8:09 am
hemant_rajput wrote:64. If x is an integer between 2 and 100 and if sqrt x is also an integer,
what is the value of x?
(1) cuberoot x is an integer.
(2) 2(cuberoot x) = sqrt x
Target question: What is the value of x?

Given: x is an integer between 2 and 100 and sqrt x is an integer.
In other words, x is the square of an integer, which means x must equal 4, 9, 16, 25, 36, 49, 64 or 81

Statement 1: cuberoot(x) is an integer.
In other words, x is the cube of an integer
Among the possible values of x (4, 9, 16, 25, 36, 49, 64, 81), only 64 is the cube of an integer.
So, x must equal 64
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: 2(cuberoot x) = sqrt x
Since the right-hand side, sqrt x, must be an integer, it must be the case that the left-hand side, 2(cuberoot x), is also an integer
So, it must be the case that EITHER cuberoot x is an integer OR cuberoot x equals some decimal ending in .5 (e.g., 3.5) so that we get an integer after multiplying by 2.
Well, among the possible values of x, none will yield decimal ending in .5, so we're looking for a value of x such that cuberoot x is an integer.
In other words, x is the cube of an integer
Among the possible values of x (4, 9, 16, 25, 36, 49, 64, 81), only 64 is the cube of an integer.
So, x must equal 64
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer = D

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by GMATGuruNY » Thu Jul 25, 2013 3:15 am
hemant_rajput wrote:64. If x is an integer between 2 and 100 and if root x is also an integer,
what is the value of x?
(1) cube root x or (x)^(1/3) is an integer.
(2) 2(cube root x) = root x
Statement 2: 2 * x^(1/3) = x^(1/2)
2 = x^(1/2) / x^(1/3)
2 = x^(1/6)
2� = x.
SUFFICIENT.

Statement 1: x^(1/3) = integer
For both x^(1/2) and x^(1/3) to be integers, x must be an integer raised to a power divisible by both 2 and 3.
The only value between 2 and 100 that satisfies this constraint is the same value yielded by statement 1: 2�.
SUFFICIENT.

The correct answer is D.
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