Q: If "K" is an integer and 3 is the remainder when K is divided by 5, how many values for K are possible when 0<k<100?
I thought the answer was "19", and it turns out to be "20". Could someone explain to me why the smallest value for K is "3"?
I started my lowest value for K as 8 where 8 / 5 = remainder 3.
How is it possible that K's lowest value could equal to "3" when clearly 3 / 5 does not yield to an integer answer with the remainder 3? Could someone refute my obvious flawed reasoning?
Integer Question - Looking for values for K
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its 20, start with 3 and then 8. 3 will be the smallest value and you can divide it as 0/5 = (5)(0) + 3. 3 is the remainder when divided by 5. it means in every 10 natural numbers their are 2 such numbers. less than 100 means that the last number will be 98. therefore, (2)(10) = 20
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Hi sorry, this did not really answer my question why the lowest value for K = 3.
I understand the subsequent integer answers STARTING from "K" integers: 8,13,18,..... up to 98 when these "K" integers are divided 5 it yields 3 as a remainder.
How is it that K integer "3" when divided by "5" could yield a remainder of "3"? So 3 divided 5= integer, Remainder 3???
I understand the subsequent integer answers STARTING from "K" integers: 8,13,18,..... up to 98 when these "K" integers are divided 5 it yields 3 as a remainder.
How is it that K integer "3" when divided by "5" could yield a remainder of "3"? So 3 divided 5= integer, Remainder 3???
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5 multiply by 0 will lead to answer 0...Remember: 0 is the multiple of every number thus u can divide 3 with 5. 3/5 = (5)(0) + 3...so include 3 and the right answer is 20
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Most students are good a listing some possible values that satisfy given information regarding remainders. However, they often miss the smallest possible value (in this case the value of 3)jkcm25 wrote:Q: If "K" is an integer and 3 is the remainder when K is divided by 5, how many values for K are possible when 0<k<100?
I thought the answer was "19", and it turns out to be "20". Could someone explain to me why the smallest value for K is "3"?
I started my lowest value for K as 8 where 8 / 5 = remainder 3.
How is it possible that K's lowest value could equal to "3" when clearly 3 / 5 does not yield to an integer answer with the remainder 3? Could someone refute my obvious flawed reasoning?
When it comes to remainders, we have a nice rule that says:
If N divided by D, leaves remainder R, then the possible values of N are R, R+D, R+2D, R+3D,. . . etc.
For example, if k divided by 5 leaves a remainder of 1, then the possible values of k are: 1, 1+5, 1+(2)(5), 1+(3)(5), 1+(4)(5), . . . etc.
Cheers,
Brent