Hey there,
can somebody please explain why 1/5 equals 0 with a remainder of 1???
Thanks!
REMAINDER PROBLEM
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Number = Quotient * divisor + remainder
7/5 means 1*5 + 2 (1 quotient, 5 divisor and 2 remainder)
19/5 means 3*5 + 4 (3 quotient, 5 divisor and 4 remainder)
Quotient represents how many times the divisor is contained in the number.
Now coming to your question: 1/5
how many times is 5 contained in 1? ZERO
What is the left over? ONE
can we write 1/5 = 0*5 + 1. Yes we can
Hence 1/5 has 0 quotient and 1 remainder.
7/5 means 1*5 + 2 (1 quotient, 5 divisor and 2 remainder)
19/5 means 3*5 + 4 (3 quotient, 5 divisor and 4 remainder)
Quotient represents how many times the divisor is contained in the number.
Now coming to your question: 1/5
how many times is 5 contained in 1? ZERO
What is the left over? ONE
can we write 1/5 = 0*5 + 1. Yes we can
Hence 1/5 has 0 quotient and 1 remainder.